Answer: Meaghan is right.
Step-by-step explanation:
For a number like:
123.45
the tens place would be the "2" (second number at the left of the decimal point)
The ones place would be the "3" (first number at the left of the decimal point)
Let's suppose that Lily is correct.
Then the quotient of:
43.61/7
Will be a number with two digits in the left of the decimal point.
The smallest number that meets this condition, is the number 10.
Then let's see:
7*10 = 70
then:
70/7 = 10
and:
43.61 < 70
(70 is larger than 43.61)
then:
43.61/7 < 70/7 = 10
Then:
(43.61/7) < 10
This means that our quotient is smaller than 10, then the first digit of the quotient can not be on the tens place.
Then Meaghan is the correct one.
We also could perform the quotient to find:
43.61/7 = 6.23
So yes, Meaghan is correct.
Answer:
21000 meters
Step-by-step explanation:
100R + 300B
100(30) + 300(60)
3000 + 18000 = 21000
Step-by-step explanation:
Replace x = 3
f(3) = 2(3) - 2
= 6 - 2
= 4
All you have to do is graph whatever those #'s are, so whatever numbers are top are the number that are on the bottom of the graph, and whatever #'s are on top are the numbers going up on the graph.
Answer:
the 2nd
Step-by-step explanation:
![\sqrt[5]{4} \times \sqrt{2 } \\ {4}^{ \frac{1}{5} } \times {2}^{ \frac{1}{2} } \\ {2}^{2 \times \frac{1}{5} } \times {2}^{ \frac{1}{2} } \\ {2}^{ \frac{2}{5} + \frac{1}{2} } \\ {2}^{ \frac{9}{10} } = \sqrt[10]{ {2}^{9} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B4%7D%20%20%20%5Ctimes%20%20%5Csqrt%7B2%20%7D%20%20%5C%5C%20%20%7B4%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%20%5Ctimes%20%20%20%7B2%7D%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%20%5C%5C%20%20%7B2%7D%5E%7B2%20%5Ctimes%20%5Cfrac%7B1%7D%7B5%7D%20%20%7D%20%20%5Ctimes%20%20%7B2%7D%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%20%5C%5C%20%20%7B2%7D%5E%7B%20%5Cfrac%7B2%7D%7B5%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%20%5C%5C%20%20%20%7B2%7D%5E%7B%20%5Cfrac%7B9%7D%7B10%7D%20%7D%20%20%3D%20%20%5Csqrt%5B10%5D%7B%20%7B2%7D%5E%7B9%7D%20%7D%20)
