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Westkost [7]
4 years ago
7

The parentheses are around 270-54, the value is _______. When the parentheses are around 54÷9, the value is _______.

Mathematics
2 answers:
Vilka [71]4 years ago
7 0

Answer:

Im pretty sure they stay the same. But that might just be me

shepuryov [24]4 years ago
6 0
They are the same!! Im not sure thi
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Meaghan and Lily are dividing 43.61 by 7. Meaghan says that the first digit of the quotient is in the ones place. Lily says it i
Ivahew [28]

Answer: Meaghan is right.

Step-by-step explanation:

For a number like:

123.45

the tens place would be the "2" (second number at the left of the decimal point)

The ones place would be the "3" (first number at the left of the decimal point)

Let's suppose that Lily is correct.

Then the quotient of:

43.61/7

Will be a number with two digits in the left of the decimal point.

The smallest number that meets this condition, is the number 10.

Then let's see:

7*10 = 70

then:

70/7 = 10

and:

43.61 < 70

(70 is larger than 43.61)

then:

43.61/7 < 70/7 = 10

Then:

(43.61/7) < 10

This means that our quotient is smaller than 10, then the first digit of the quotient can not be on the tens place.

Then Meaghan is the correct one.

We also could perform the quotient to find:

43.61/7 = 6.23

So yes, Meaghan is correct.

5 0
3 years ago
Keya is training for a duathlon competition comprised of running and biking. Her training involves running for LaTeX: RR minutes
balu736 [363]

Answer:

21000 meters

Step-by-step explanation:

100R + 300B

100(30) + 300(60)

3000 + 18000 = 21000

6 0
4 years ago
F(x) = 2x - 2<br> Find f(3)
guajiro [1.7K]

Step-by-step explanation:

Replace x = 3

f(3) = 2(3) - 2

= 6 - 2

= 4

8 0
3 years ago
Read 2 more answers
Help, I’m no good with slope
postnew [5]

All you have to do is graph whatever those #'s are, so whatever numbers are top are the number that are on the bottom of the graph, and whatever #'s are on top are the numbers going up on the graph.

5 0
4 years ago
Rewrite 5√4 * √2 as a single radical.
melisa1 [442]

Answer:

the 2nd

Step-by-step explanation:

\sqrt[5]{4}   \times  \sqrt{2 }  \\  {4}^{ \frac{1}{5} }   \times   {2}^{ \frac{1}{2} }  \\  {2}^{2 \times \frac{1}{5}  }  \times  {2}^{ \frac{1}{2} }  \\  {2}^{ \frac{2}{5}  +  \frac{1}{2} }  \\   {2}^{ \frac{9}{10} }  =  \sqrt[10]{ {2}^{9} }

8 0
3 years ago
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