All categories

3 years ago

In the first week

Mathematics

1 answer:

FromTheMoon [43]3 years ago

8 0

The percent change in the number of people who went to the pool

between the first and last week is 10% less

Step-by-step explanation:

The given is:

In the first week of July, a record 1,060 people went to the local swimming pool
In the second week, 105 fewer people went to the pool
In the third week, 135 more people went to the pool than in the second week
In the fourth week, 136 fewer people went to the pool than in the third week

We need to find the percent change in the number of people who

went to the pool between the first and last weeks

∵ There were 1060 people in the 1st week

∵ There were 105 fewer people in the 2nd week

∴ The number of people in the 2nd week = 1060 - 105 = 955

∴ There were 955 people in the 2nd week

∵ There were 135 more people in the 3rd week than the 2nd week

∵ There were 955 people in the 2nd week

∴ The number of people in the 3rd week = 955 + 135 = 1090

∴ There were 1090 people in the 3rd week

∵ There were 136 fewer people in the 4th week than in the 3rd week

∵ There were 1090 people in the 3rd week

∴ The number of people in the 4th week = 1090 - 136 = 954

∴ There were 954 people in the 4th week

Let us find the change from 1st week to last week

∵ There were 1060 people in the 1 st week

∵ There were 954 people in the last week

∴ The change = 1060 - 954 = 106

∵ Percent change = $\frac{Change}{Original}$ × 100%

∴ Percent change = $\frac{106}{1060}$ × 100%

∴ Percent change = 10%

The percent change in the number of people who went to the pool

between the first and last week is 10% less

Learn more:

You can learn more about percentage in brainly.com/question/12501490

#LearnwithBrainly

You might be interested in

Solve for a^2+b^2=c^2

Kay [80]

In this equation, there is nothing to solve for. However, the expression $a^{2} + b^{2} = c^{2}$ is the Pythagorean theorem. If there is a right triangle, then when the lengths of two shorter legs (a and b) are added together, and then square rooted, you get c, which is the hypotenuse.

Hope this helps!

5 0

3 years ago

In this problem, we explore the effect on the standard deviation of adding the same constant to each data value in a data set. C

aliya0001 [1]

Answer:

3.6661

A, Adding a constant does nothing to the standard deviation

Step-by-step explanation:

I'm gonna assume s=standard deviation

The standard deviation is just the square root of the second moment minus the first moment squared

Because we were not told otherwise I think it's pretty safe to assume that all events are equally likely

Let's start by calculating the first moment (AKA The mean)

1/5(8+16+14+8+16)= 12.4

Let's then find the second moment

1/5(8²+16²+14²+8²+16²)= 167.2

√(167.2-12.4²)=3.6661

While I could just tell you that adding something to the standard deviation (and the variane as well) doesn't do anything let's calculate it for fun

same process

.2(16+24+22+16+24)= 20.4

.2(16²+24²+22²+16²+24²)=429.6

√(429.6-20.4²)= 3.6661

6 0

3 years ago

12/18 reduced to the lowest term

melomori [17]

2/3 is it's simplified form

8 0

3 years ago

Penelope determined the solutions of the quadratic function by completing the square. F(x) = 4x2 8x 1 –1 = 4x2 8x –1 = 4(x2 2x)

Ymorist [56]

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

<h3>What is quadratic equation ?</h3>

Any equation of the form $ax^2+bx+c=0$ where x is variable and a, b, and c are any real numbers where a ≠ 0 is called quadratic equation .

Given work of Penelope is

$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+1=4\left(x^{2}+2 x+1\right) \\&0=4(x+2)^{2} \\&0=(x+2)^{2} \\&0=x+2 \\&-2=x\end{aligned}$

Now we can see that Penelope determined the solutions of the quadratic function by completing the square. so he must have been done as following

$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+4=4\left(x^{2}+2 x+1\right) \\&3=4(x+2)^{2} \\&\frac{3}{4} =x+2)^{2} \\&\frac{\pm\sqrt3}{2} =x+2 \\&\frac{-2\pm\sqrt3}{2} =x\end{aligned}$

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

To learn more about quadratic equations visit : brainly.com/question/1214333

8 0

2 years ago

Use the discriminant to determine how many and what kind of solutions the quadratic equation 3x^2 + 4x = - 5 has.

leonid [27]

Answer:

Step-by-step explanation:

7 0

3 years ago