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zysi [14]
4 years ago
8

Witch multiples of 24 are not factors of 24

Mathematics
1 answer:
Nataly [62]4 years ago
8 0

Answer:

A factor of 24 is a number that can be multilied by another number (normally whole (not fraction or decimal) numbers) so a factor must be less than the number any multiple of 2 greater than 24 will work so just any even number greater than 24 exg 26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60, and so on.

Step-by-step explanation:


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The length of the sides of a triangular garden are 10m 11m 13m.Find the measure of the angle opposite the longest side to the ne
Kaylis [27]
C^2=a^2+b^2-2abcosC
13^2=10^2+11^2-2×10×11×cos(°)
169=100+121-220cos(°)
220cos(°)=100+121-169
220cos(°)=52
cos(°)= 13/55
°=cos-1(13/55)
°=76.328°
3 0
3 years ago
Can someone help me with B? I’m really bad at this kind of stuff. I need help ASAP
Vinil7 [7]

Answer:

D = .44P

Step-by-step explanation:

We need to find the slope of the line

m = (y2-y1)/ (x2-x1)

Using two points

m = (22-4.4) /(50-10)

   = 17.6/40

   = .44 lb/ in^2 ft

We can use the point slope form of the equation

y-y1 = m(x-x1)  where y=D and x=P

D-4.4 = .44 (P-10)

Distribute

D-4.4 = .44P - 4.4

Add 4.4 to each side

D -4.4+4.4 = .44P -4.4+4.4

D = .44P

8 0
3 years ago
Read 2 more answers
Claire thinks that if she draws a parallelogram with 2 congruent sides, it must be a rhombus. Jacob thinks that she would need t
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Yes it is ok if she draws a parallelogram
5 0
3 years ago
Your friend asks if you would like to play a game of chance that uses a deck of cards and costs $1 to play. They say that if you
gtnhenbr [62]

Answer:

Expected value = 40/26 = 1.54 approximately

The player expects to win on average about $1.54 per game.

The positive expected value means it's a good idea to play the game.

============================================================

Further Explanation:

Let's label the three scenarios like so

  • scenario A: selecting a black card
  • scenario B: selecting a red card that is less than 5
  • scenario C: selecting anything that doesn't fit with the previous scenarios

The probability of scenario A happening is 1/2 because half the cards are black. Or you can notice that there are 26 black cards (13 spade + 13 club) out of 52 total, so 26/52 = 1/2. The net pay off for scenario A is 2-1 = 1 dollar because we have to account for the price to play the game.

-----------------

Now onto scenario B.

The cards that are less than five are: {A, 2, 3, 4}. I'm considering aces to be smaller than 2. There are 2 sets of these values to account for the two red suits (hearts and diamonds), meaning there are 4*2 = 8 such cards out of 52 total. Then note that 8/52 = 2/13. The probability of winning $10 is 2/13. Though the net pay off here is 10-1 = 9 dollars to account for the cost to play the game.

So far the fractions we found for scenarios A and B were: 1/2 and 2/13

Let's get each fraction to the same denominator

  • 1/2 = 13/26
  • 2/13 = 4/26

Then add them up

13/26 + 4/26 = 17/26

Next, subtract the value from 1

1 - (17/26) = 26/26 - 17/26 = 9/26

The fraction 9/26 represents the chances of getting anything other than scenario A or scenario B. The net pay off here is -1 to indicate you lose one dollar.

-----------------------------------

Here's a table to organize everything so far

\begin{array}{|c|c|c|}\cline{1-3}\text{Scenario} & \text{Probability} & \text{Net Payoff}\\ \cline{1-3}\text{A} & 1/2 & 1\\ \cline{1-3}\text{B} & 2/13 & 9\\ \cline{1-3}\text{C} & 9/26 & -1\\ \cline{1-3}\end{array}

What we do from here is multiply each probability with the corresponding net payoff. I'll write the results in the fourth column as shown below

\begin{array}{|c|c|c|c|}\cline{1-4}\text{Scenario} & \text{Probability} & \text{Net Payoff} & \text{Probability * Payoff}\\ \cline{1-4}\text{A} & 1/2 & 1 & 1/2\\ \cline{1-4}\text{B} & 2/13 & 9 & 18/13\\ \cline{1-4}\text{C} & 9/26 & -1 & -9/26\\ \cline{1-4}\end{array}

Then we add up the results of that fourth column to compute the expected value.

(1/2) + (18/13) + (-9/26)

13/26 + 36/26 - 9/26

(13+36-9)/26

40/26

1.538 approximately

This value rounds to 1.54

The expected value for the player is 1.54 which means they expect to win, on average, about $1.54 per game.

Therefore, this game is tilted in favor of the player and it's a good decision to play the game.

If the expected value was negative, then the player would lose money on average and the game wouldn't be a good idea to play (though the card dealer would be happy).

Having an expected value of 0 would indicate a mathematically fair game, as no side gains money nor do they lose money on average.

7 0
2 years ago
Solve 7 x - 15 = -2.
Arisa [49]
7x-15=-2 Move -15 to the rigjt side, 7x=-2+15 7x=13 Divide both sides by 7, 7x/7=13/7 x=13/7
6 0
3 years ago
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