The end point for a 192 degree angle is located in the third quadrant, where both x and y are negative, so both sin192, cos192 are negative.
Answer= x³+4x²+16x+64
Expand the following:(x + 4 i) (x - 4 i) (x + 4)
(x - 4 i) (x + 4) = (x) (x) + (x) (4) + (-4 i) (x) + (-4 i) (4) = x^2 + 4 x - 4 i x - 16 i = -16 i + (4 - 4 i) x + x^2:
-16 i + (-4 i + 4) x + x^2 (4 i + x)
| | | | x | + | 4 i
| | x^2 | + | (4 - 4 i) x | - | 16 i
| | | | (-16 i) x | + | 64
| | (4 - 4 i) x^2 | + | (16 + 16 i) x | + | 0
x^3 | + | (4 i) x^2 | + | 0 | + | 0
x^3 | + | 4 x^2 | + | 16 x | + | 64:
Answer: x^3 + 4 x^2 + 16 x + 64
Answer: 145
Step-by-step explanation:
Answer:
x=14/3
Step-by-step explanation:
According to the corresponding angles theorem, when parallel lines are cut by a transversal, the corresponding angles are congruent. These 3 lines are all parallel, so 70 = 12x +14.
Subtract 14 from both sides
56 = 12x
Divide both sides by 12
14/3 = x
x=14/3
