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daser333 [38]
3 years ago
6

What is the period, in seconds, of a simple pendulum of length 2 meters? Use the gravitational constant g = 9.8 m/s^2 and round

your answer to two decimal places.
Mathematics
1 answer:
kirill [66]3 years ago
8 0

Answer:

The period, in seconds to two decimal places is, 2.84 sec

Step-by-step explanation:

Using formula:

T = 2 \pi \sqrt{\frac{l}{g}}             ......[1]

where

T represents the Time period in second

l represents the length of the pendulum/

As per the statement:

Use the gravitational constant g = 9.8 m/s^2 , length of the simple pendulum(l) = 2 meters and \pi = 3.14

Substitute the given values we have;

T = 2\cdot 3.14 \cdot \sqrt{\frac{2}{9.8}}

⇒T = 6.28 \cdot \sqrt{\frac{1}{4.9}}=6.28 \cdot \frac{1}{2.21359436212}= \frac{6.28}{2.21359436212} = 2.83701481512

Therefore, the period, in seconds to two decimal places is, 2.84 sec

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Answer:

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Step-by-step explanation:

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multiply second equation by -2

-2 × (9M + 5S) = $65

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8M + 10S - 18M - 10S = $80 - $130 (10S will eliminate -10S)

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3 years ago
On Monday, Jullo ran 39 miles. On Tuesday, he ran another
Artist 52 [7]
<h3>Answer:</h3>

67 miles

<h3>Step-by-step explanation:</h3>

On Monday, Jullo ran <u>39 miles.</u>

  • ⇒ Monday = 39 miles

On Tuesday, he ran <u>24 miles.</u>

  • ⇒ Tuesday = 24 miles

On Wednesday, he ran <u>4 miles.</u>

  • ⇒ Wednesday = 4 miles

<u>Finding the total miles:</u>

Total miles ran on Monday, Tuesday, and Wednesday = 39 + 24 + 4

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Step-by-step explanation:

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Step-by-step explanation:

Substitute x=2 and y=5 into equation

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