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daser333 [38]
3 years ago
6

What is the period, in seconds, of a simple pendulum of length 2 meters? Use the gravitational constant g = 9.8 m/s^2 and round

your answer to two decimal places.
Mathematics
1 answer:
kirill [66]3 years ago
8 0

Answer:

The period, in seconds to two decimal places is, 2.84 sec

Step-by-step explanation:

Using formula:

T = 2 \pi \sqrt{\frac{l}{g}}             ......[1]

where

T represents the Time period in second

l represents the length of the pendulum/

As per the statement:

Use the gravitational constant g = 9.8 m/s^2 , length of the simple pendulum(l) = 2 meters and \pi = 3.14

Substitute the given values we have;

T = 2\cdot 3.14 \cdot \sqrt{\frac{2}{9.8}}

⇒T = 6.28 \cdot \sqrt{\frac{1}{4.9}}=6.28 \cdot \frac{1}{2.21359436212}= \frac{6.28}{2.21359436212} = 2.83701481512

Therefore, the period, in seconds to two decimal places is, 2.84 sec

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