Answer:
A. sec =12/13×
B. COS =12/13×
C. tan =12/5✓
D. sin =12/13 ✓
Step-by-step explanation:
we know,
using Pythagoras formula,
p=12,h=13 ,b=?
h^2 =p^2 +b^2
b=5
so tan = p/b
=12/5
sin=p/h and cosec= h/p
D. sin =12/13
Answer:
The value of y is 64.
Step-by-step explanation:
The given equation is
![y=(\frac{1}{4})^x](https://tex.z-dn.net/?f=y%3D%28%5Cfrac%7B1%7D%7B4%7D%29%5Ex)
It is given that (-3, y) lies on the graph of y. It means the equation of the function must be satisfy by the point (-3,y).
Substitute x=-3 in the given equation to find the value of y,
![y=(\frac{1}{4})^{-3}](https://tex.z-dn.net/?f=y%3D%28%5Cfrac%7B1%7D%7B4%7D%29%5E%7B-3%7D)
![(\frac{a}{b})^{-n}=(\frac{b}{a})^n](https://tex.z-dn.net/?f=%28%5Cfrac%7Ba%7D%7Bb%7D%29%5E%7B-n%7D%3D%28%5Cfrac%7Bb%7D%7Ba%7D%29%5En)
![y=64](https://tex.z-dn.net/?f=y%3D64)
Therefore the value of y is 64.
Answer:
$2.89
Step-by-step explanation:
$14.45/ 5= 2.89
Answer:
He drove 111 miles
If we were given the distance Lan drove last weekend instead off how much gas he used then we would have to find the amount of gas used by lan.
Step-by-step explanation:
Ian's car can go 185 miles on 5 gallons of gas
On 5 gallons of gas lan's car can go 185 miles
Therefore in gallon of gas lan 's car can go
185/5 = 37
So, for 3 gallons of gas lan's car can go
3 × 37 = 111
for 3 gallons of gas lan's car can go 111 miles
If we were given the distance Lan drove last weekend instead off how much gas he used then we would have to find the amount of gas used by lan.