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GREYUIT [131]
4 years ago
15

I need to find the measurements of the angles 1,2,3,and 4

Mathematics
1 answer:
Sonja [21]4 years ago
4 0
1)40 2) 75 3)105 4)140
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The product of two consecutive numbers is 4 more than three times the larger. find the integer​
Stella [2.4K]

Answer:

Step-by-step explanation:

Let the first integer be x, then the next is x+1.

x(x + 1) = 3(x + 1) + 4

x^2 + x = 3x+ 3 + 4

x^2 + x - 3x - 7 = 0

x^2 - 2x - 7 = 0

Solving this does not give an integer so maybe there's something wrong with the question??

7 0
3 years ago
Relationships between x and y
marta [7]

Answer:

they love each other

Step-by-step explanation:

...........

6 0
3 years ago
Read 2 more answers
An empty box is shaped like a rectangular prism. the box has a base area of '9/10' square foot and a height of '1/3' foot. How m
maxonik [38]

Answer:3/10

Step-by-step explanation:

9  divided by 3 is 3 so that it

Next to 3/10 the denominator away stays the same,

3 0
3 years ago
Factor completely 3x2 - 21.
VMariaS [17]
3x² - 21

Factor 3 from both terms:

3 (x² - 7)

To me, that's as far as you should need to go.  But if you want to get
completely carried away, you could go one step further, since you have
the difference of two squares:

3 (x + √7) (x - √7)

Of course, there's no end now, because the last binomial could be
considered another difference of two squares, so you'd have to
factor that too:

3 (x + √7) (√x + ⁴√7) (√x - ⁴√7)

but to me, this would be nonsense.
6 0
3 years ago
Read 2 more answers
Can't figure it out!!
Zanzabum
\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= \cfrac{1}{x}  \qquad 
\begin{cases}
x_1=2\\
x_2=b
\end{cases}\implies \cfrac{f(b)-f(2)}{b-2}=-\cfrac{1}{10}
\\\\\\
\cfrac{\frac{1}{b}-\frac{1}{2}}{b-2}=-\cfrac{1}{10}\implies 
\cfrac{\frac{2-b}{2b}}{b-2}=-\cfrac{1}{10}\implies \cfrac{2-b}{2b}=-\cfrac{b-2}{10}
\\\\\\


\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying
\\\\\\
2b^2-4b-10b+20=0\implies 2b^2-14b+20=0
\\\\\\
b^2-7b+10=0\implies 
(b-2)(b-5)=0\implies b=
\begin{cases}
\boxed{5}\\
2
\end{cases}
8 0
3 years ago
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