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d1i1m1o1n [39]
3 years ago
9

300% increase written as a decimal is ______ and written as a fraction is ___

Mathematics
2 answers:
erica [24]3 years ago
8 0
In decimal 3 and in fraction 300/100
emmainna [20.7K]3 years ago
4 0

Answer: 3 and 300/100

Step-by-step explanation:

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Work out the balance for 1500 invested for 2 years at 3.7% per annum.
Andru [333]
1500 x 1.037 = 1555.50
1555.50 x 1.037 = 1613.05
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Two inetgers that are the same distance from 0 on a number line but opposite sides of 0 are called
IrinaVladis [17]
Additive inverses, because their sum is 0
7 0
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thank you for hurrying here is the very last one Explain how you would find the perimeter of this triangle.
Lena [83]

Step-by-step explanation:

Use the method of TOA CAH SOH.

tan(51.3) =  \frac{opp}{adj}  \\  \tan(51.3)  =  \frac{u}{4}  \\ u = 4 \tan(51.3)

cos(51.3)  =  \frac{adj}{hypo}  \\  \cos(51.3)  =  \frac{4}{v}  \\ v \cos(51.3)  = 4 \\ v =  \frac{4}{ \cos(51.3) }

Perimeter of triangle = Sum of all sides =

u \:  +  \: v + 4

5 0
3 years ago
Read 2 more answers
Find, correct to the nearest degree, the three angles of the triangle with the vertices d(0,1,1), e( 2, 4,3) − , and f(1, 2, 1)
Ksju [112]
Well, here's one way to do it at least... 

<span>For reference, let 'a' be the side opposite A (segment BC), 'b' be the side opposite B (segment AC) and 'c' be the side opposite C (segment AB). </span>

<span>Let P=(4,0) be the projection of B onto the x-axis. </span>
<span>Let Q=(-3,0) be the projection of C onto the x-axis. </span>

<span>Look at the angle QAC. It has tangent = 5/4 (do you see why?), so angle A is atan(5/4). </span>

<span>Likewise, angle PAB has tangent = 6/3 = 2, so angle PAB is atan(2). </span>

<span>Angle A, then, is 180 - atan(5/4) - atan(2) = 65.225. One down, two to go. </span>

<span>||b|| = sqrt(41) (use Pythagorian Theorum on triangle AQC) </span>
<span>||c|| = sqrt(45) (use Pythagorian Theorum on triangle APB) </span>

<span>Using the Law of Cosines... </span>
<span>||a||^2 = ||b||^2 + ||c||^2 - 2(||b||)(||c||)cos(A) </span>
<span>||a||^2 = 41 + 45 - 2(sqrt(41))(sqrt(45))(.4191) </span>
<span>||a||^2 = 86 - 36 </span>
<span>||a||^2 = 50 </span>
<span>||a|| = sqrt(50) </span>

<span>Now apply the Law of Sines to find the other two angles. </span>

<span>||b|| / sin(B) = ||a|| / sin(A) </span>
<span>sqrt(41) / sin(B) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(41) / sqrt(50) = sin(B) </span>
<span>.8222 = sin(B) </span>
<span>asin(.8222) = B </span>
<span>55.305 = B </span>

<span>Two down, one to go... </span>

<span>||c|| / sin(C) = ||a|| / sin(A) </span>
<span>sqrt(45) / sin(C) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(45) / sqrt(50) = sin(C) </span>
<span>.8614 = sin(C) </span>
<span>asin(.8614) = C </span>
<span>59.470 = C </span>

<span>So your three angles are: </span>

<span>A = 65.225 </span>
<span>B = 55.305 </span>
<span>C = 59.470 </span>
8 0
3 years ago
How many different 4-digit numerals can be made from the digits of 56987 if a digit can appear just once in a numeral?
In-s [12.5K]

Answer: 120

Step-by-step explanation:

Given : the total number of digits : 5

The number of permutations of n things taken r at a time is given by :-

\dfrac{n!}{(n-r)!}

By using permutation, the number of different 4-digit numerals can be made from the digits of 56987 is given by :-

^5P_4=\dfrac{5!}{(5-4)!}=5!=120

Hence, the number of different 4-digit numerals can be made from the digits of 56987 is 120 .

8 0
4 years ago
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