Explain which type of graph would best display showing the temp. of a liquid

Wolves have good endurance and have been known to travel long distances-up to about 60 miles-in one night.If a wolf trots 18 4/5

leva [86]

Answer:

8 2/35 miles per hour

Step-by-step explanation:

We are given distance traveled and the time required. We can use those directly in the relation that gives speed:

speed = distance / time

... = (18 4/5 miles)/(2 1/3 hours)

... = (94/5 miles)/(7/3 hours) . . . . . . converte mixed numbers to improper fractions

... = (94/5×3/7) miles/hour . . . . . . . "invert and multiply"

.. = 282/35 miles/hour . . . . . . . . . . improper fraction result

... = 8 2/35 miles/hour . . . . . . . . . . as a mixed number

5 0

3 years ago

-1/2+c=31/4 A. C=33/4 B. C=8 C. 29/4 D. 7

kkurt [141]

Answer:

A

Step-by-step explanation:

-1/2+c=31/4

-1/2+c+1/2=31/4+1/2

c=33/4

4 0

3 years ago

A county is considering rasing the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 m

DochEvi [55]

Answer:

No, at alpha equals 0.10, we do not have enough evidence to support the county's claim.

Step-by-step explanation:

We are given that a county is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 30 miles per hour.

A random sample of 15 vehicles has a mean speed of 31 miles per hour and a standard deviation of 4.7 miles per hour.

Let $\mu$ = true mean speed of the vehicles.

SO, Null Hypothesis, $H_0$ : $\mu \leq$ 30 miles per hour {means that the mean speed of vehicles is lesser than or equal to 30 miles per hour}

Alternate Hypothesis, $H_A$ : $\mu$ > 30 miles per hour {means that the mean speed of vehicles is greater than 30 miles per hour}

The test statistics that will be used here is One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean speed of 15 vehicles = 31 mph

s = sample standard deviation = 4.7 mph

n = sample of vehicles = 15

So, test statistics = $\frac{31-30}{\frac{4.7}{\sqrt{15} } }$ ~ $t_1_4$

= 0.824

Hence, the value of test statistics is 0.824.

Now at 0.10 significance level, the t table gives critical value of 1.345 at 14 degree of freedom for right-tailed test. Since our test statistics is less than the critical value of t as 0.824 < 1.345, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean speed of vehicles is lesser than or equal to 30 miles per hour which means that the county's claim is not supported.

4 0

3 years ago

Someone please help with this question :)!

Elodia [21]

I think a) would be the answer. I proceeded by elimination: the domaine of the function goes from 3 and continues to infinity, so that leaves with a) and b) as possible answers. Both have the same range and both of their functions reflect over the x axis, so we have to compare the two answer by looking at the position of the function in the graph. The function is in the first quadrant (top right corner), so the position of the function has to be at our right, which leads us to a).

3 0

2 years ago

Find the x and y intercepts of the graph of the equation y=x^2-5

mr_godi [17]

Answer:

x intercepts -sqrt(5), + sqrt(5)

y intercept -5

Step-by-step explanation:

y = x^2 -5

to find the x intercept set y=0 and solve for x

0 = x^2-5

add 5 to each side

5 = x^2

take the square root of each side

+- sqrt(5) = sqrt(x^2)

x = +-sqrt(5) there are 2 x intercepts since it is a quadratic

to find the y intercept set x=0 and solve for y

y = 0-5

y = -5

8 0

3 years ago