perpendicular lines have a slope that is a negative reciprocal
A) 4x-5y=5
subtract 4x
solve for y
-5y = -4x+5
divide by -5
y = 4/5 x+5 slope is 4/5 perpendicular slope is -5/4
y -y1 =m(x-x1) point slope form of a line
y-3 = -5/4 (x-5)
B) 5x+4y = 37
subtract 5x
4y =-5x +37
divide by 4
y =-5/4 x +37/4 slope is -5/4 perpendicular slope is 4/5
y -y1 =m(x-x1) point slope form of a line
y-3 = 4/5 (x-5)
C)4x+5y=5
subtract 4x
5y = -4x +5
divide by 5
y = -4/5 x +1
y =-4/5 x +1 slope is -4/5 perpendicular slope is 5/4
y -y1 =m(x-x1) point slope form of a line
y-3 = 5/4 (x-5)
D)5x-4y=8
subtract 5x
-4y = -5x+8
divide by -4
y = 5/4 x-2
y =5/4 x +-2 slope is 5/4 perpendicular slope is -4/5
y -y1 =m(x-x1) point slope form of a line
y-3 = -4/5 (x-5)
It would be 48 bc if you add it all up and subtract it and add again and multiply and divide and multiply within a and the substance of present after 6 yr you will see that i have wasted your time and that is not the answer
Answer:
length = 7
pls mark me the brainliest
Step-by-step explanation:
A = Lw
35 = x (x -2)
35 = x2 - 2x
x2 -2x -35 = 0
(x-7)(x+5) = 0
x-7=0
x=7 (we won't use the other factor since it would give us a negative length
so length = 7
Answer:
r= -1/5
Step-by-step explanation:
Step 1: Remove the parentheses (5r-10= -51)
Step 2: Move the constant to the right-hand side and change the sign (5r= -51 + 50)
Step 3: Calculate the sum of -51 +50 (5r = -1)
Last Step: Divide both sides by the equation by 5 (r = -1/5)
The midpoint is (7,4.75) so the y-coordinate should be y=4.75. I hope that helps