(6,1)&(5,4)
(7,-3)&(4,-8)
(-8,0)&(1,5)
Basically, you are to find the line that passes through 2 points.
Equation: y2-y1=m(x2-x1)
• x1: 6, x2: 5, y1: 1, y2: 4
(4-1)/(5-6)=m
m=3/-1
m=-3
Hence, m= -3x10^0
• x1: 7, x2: 4, y1: -3, y2: -8
(-8--3)/(4-7)=m
m=(-8+3)/-3
m=-5/-3
m=5/3
m=1.66666667
Hence, m=1.6667x10^0
• x1: -8, x2: 1, y1: 0, y2: 5
(5-0)/(1--8)=m
m=5/(1+8)
m=5/9
m=0.55555556
Hence, m=5.56x10^-1
Hope this helps!
-(-2x-6y=-16)
2x+6y=16
4x-6y=-58
Y's cancel out, then add the rest
6x=-42
divide both sides by six
x=-7
plug x into any previous equation
2(-7)+6y=16
-14+6y=16
6y=30
y=5
The answer for this is 10
Answer:
A.4x+2
Step-by-step explanation:
distrubuve property,u multiply the numbers in the bracket by two.so,2x2=4 and 2x1=2 so 4x+2
