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Nadusha1986 [10]
3 years ago
15

3 out of every 5 students in Mrs. Wilson's class have brown eyes. There are 20 students in Mrs. Wilson's class. How many of the

students in Mrs. Wilson's class have brown eyes?
3
5
10
12
Mathematics
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

12

Step-by-step explanation:

Have a nice day!

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Serggg [28]

I bet the sum you're referring to is supposed to be

\displaystyle \sum_{r=0}^{20} r^2 \times {}^{20}C_r

or equivalently,

\displaystyle \sum_{r=0}^{20} r^2 \binom{20}r

where \binom nk = \frac{n!}{k!(n-k)!} is the binomial coefficient.

Recall the binomial series,

(1+x)^\alpha = \displaystyle \sum_{r=0}^\infty \binom\alpha r x^r

which is valid for |x| < 1. (Note that if r > α, the binomial coefficient is defined to be zero, so there really are only α many terms when α is a whole number.)

Differentiating both sides with respect to x gives

\alpha (1+x)^{\alpha-1} = \displaystyle \sum_{r=0}^\infty r \binom\alpha r x^{r-1}

Multiply both sides by some arbitrary x in |x| < 1 :

\alpha x (1+x)^{\alpha-1} = \displaystyle \sum_{r=0}^\infty r \binom\alpha r x^r

Repeat:

\alpha (1+x)^{\alpha-1} + \alpha(\alpha-1) x(1+x)^{\alpha-2} = \displaystyle \sum_{r=0}^\infty r^2 \binom\alpha r x^{r-1}

\alpha x (1+x)^{\alpha-1} + \alpha(\alpha-1) x^2 (1+x)^{\alpha-2} = \displaystyle \sum_{r=0}^\infty r^2 \binom\alpha r x^r

Let α = 20, and let x approach 1 from below. The right side converges to the sum we want, while the left side converges to

20 \times 2^{19} + 20\times19\times 2^{18} = (20 + 10\times19)\times2^{19} = \boxed{210\times2^{19}}

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2 years ago
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Answer:

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Step-by-step explanation:

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This question is incomplete add context and I’ll be able to answer it probably
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suppose a computer virus begins by infecting 8 computers in the first hour after it is released .Each hour after that each newly
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Answer: (the function is 8^X, not 8X.)


Step-by-step explanation:

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