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3 years ago

Which is a possible way to rewrite the equation y=3x+3b solve for b?

Mathematics

2 answers:

Ksivusya [100]3 years ago

8 0

Move b to one side
=4b=3x
Therefore b= 3/4

son4ous [18]3 years ago

8 0

Y = 3x +3b

y -3x = 3b divide both sides by 3

(y-3x)/3 = b

hope helped

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The product of 10 and 2 more than a number is 240. Find the number.

Maurinko [17]

Answer:

The number is 220

Step-by-step explanation:

Let n represent the number

10(2) + n = 240

20 + n = 240

240 - 20 = 220

n = 220

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3 years ago

Given the function f(x) = 7x^2 − 2x + 5. Calculate the following values:

seropon [69]

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3 years ago

11 points!!!!!!! and brainiest

BartSMP [9]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

How do I factor 14x^2-7xy-147y^2

Viefleur [7K]

STEP 1

Equation at the end of step

((14 • (x2)) - 7xy) - (3•72y2)

Equation at the end of step 2

((2•7x2) - 7xy) - (3•72y2)

STEP 3

STEP 4

Pulling out like terms

4.1 Pull out like factors :

14x2 - 7xy - 147y2 = 7 • (2x2 - xy - 21y2)

Trying to factor a multi variable polynomial :

4.2 Factoring 2x2 - xy - 21y2

Try to factor this multi-variable trinomial using trial and error

Found a factorization : (2x - 7y)•(x + 3y)

6 0

3 years ago

(b) how many measurements must be averaged to get a margin of error of ±0.0001 with 98% confidence? (round your answer up to the

goblinko [34]

Given that the scale readings of the laboratory scale is normally distributed with an unknown mean and a standard deviation of 0.0002 grams.

Part A:

If the weight is weighted 5 times and the mean weight is 10.0023 grams, the 98% confidence interval for μ, the true mean of the scale readings is given by:

$98\% \ C. \ I.=\bar{x}\pm z_{\alpha/2}\left(\frac{\sigma}{\sqrt{n}}\right) \\ \\ =10.0023\pm2.33\left(\frac{0.0002}{\sqrt{5}}\right) \\ \\ =10.0023\pm2.33(0.000089) \\ \\ =10.0023\pm0.00021 \\ \\ =(10.0023-0.00021, \ 10.0023+0.00021) \\ \\ =(10.0021, \ 10.0025)$

Thus, we are 98% confidence that the true mean of the scale readings is between 10.0021 and 10.0025.

Part B:

To get a margin of error of +/- 0.0001 with a 98% confidence, then

$\pm z_{\alpha/2}\left(\frac{\sigma}{\sqrt{n}}\right)=\pm0.0001 \\ \\ \Rightarrow2.33\left(\frac{0.0002}{\sqrt{n}}\right)=0.0001 \\ \\ \Rightarrow\left(\frac{0.0002}{\sqrt{n}}\right)= \frac{0.0001}{2.33} =0.0000429 \\ \\ \Rightarrow\sqrt{n}= \frac{0.0002}{0.0000429} =4.66 \\ \\ \Rightarrow n=4.66^2=21.7156\approx22$

Therefore, the number of <span>measurements that must be averaged to get a margin of error of ±0.0001 with 98% confidence is 22.</span>

8 0

3 years ago