Answer:
E. They decrease the rate at which Ras hydrolyzes GTP.
Explanation:
Activated Ras has GTP bound to it, this propagates an intracellular signal to the nucleus where cell proliferation is induced. Thereafter proliferation is switched off by the hydrolysis of the bound GTP to GDP.
Therefore decreasing the rate of GTP hydrolysis causes Ras to remain active, ultimately leading to uncontrollable proliferation characteristic of cancer.
The answer would be ''Y-Chromosomes Analysis''
Answer:
solve it yourself lazy boy
Explanation:
<3
Answer:
i dont understand what do you mean. theres a spelling mistake
Explanation:
<span> Basically the male will have CC, the hen will have cc, and neither of them will have I. The key thing is that _all_ the chicks are coloured.
The male must have at least 1 C to be coloured, and cannot possess the dominant I. The hen has cc and/or an I to not be coloured.
That one chick is coloured would tell you little - only that the hen couldn't have 2 inhibitor alleles because otherwise the chick would have to have one and it doesn't.
However, for all of many chicks to be coloured, that means that the hen can't have any inhibitor alleles (otherwise around 50% would be white for that reason alone).
So to be colourless, the hen must be cc. However, if the male had only 1 colour allele (ie it was Cc) that would still mean that 50% of the chicks would be Cc (daddy's 'c' and one of mummy's 'c's).
Hope this helps please award brainly :)
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