Male sperm enter woman’s ovaries through sexual intercourse creating an embryo.
Answer:
Humoral immunity protects the body against extracellular pathogens and their toxins. Cell-mediated immunity protects the body against intracellular pathogens. Recognises pathogens in circulating in blood or lymph.
celluler immunity is very specific compared with humoral
Answer:
Plants, algae, cyanobacteria, and etc.
Explanation:
<em>"Most </em><em>plants, most algae, and cyanobacteria perform photosynthesis</em><em>; such organisms are called photoautotrophs. Photosynthesis is largely responsible for producing and maintaining the oxygen content of the Earth's atmosphere, and supplies most of the energy necessary for life on Earth."</em>
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Answer:
- time: 1.122 seconds
- range: 10.693 m
- maximum height: 1.543 m
Explanation:
<u>Given</u>:
runner is launched at 30° angle to horizontal at 11 m/s
acceleration due to gravity is g = -9.8 m/s²
<u>Find</u>:
runner's hang time
runner's distance to the landing point
runner's maximum height
<u>Solution</u>:
The (horizontal, vertical) speed components will be ...
(11 m/s)(cos(30°), sin(30°)) = (5.5√3 m/s, 5.5 m/s)
The time of flight can be found from the height formula:
h(t) = 1/2gt² +vt . . . . . . where v is the vertical speed at launch
The time we're concerned with is the time when h(t)=0 and t>0.
0 = -4.9t^2 +5.5√3t = t(-4.9t +5.5√3)
The second factor is zero when ...
t = (5.5√3)/4.9 ≈ 1.122 . . . seconds hang time
__
The distance to the landing point will be the product of horizontal speed and hang time:
d = (5.5 m/s)(5.5√3/4.9 s) ≈ 10.693 m . . . . distance to landing
__
The maximum height can be found from the formula (based on conversion of kinetic energy to potential energy) ...
h = v²/|2g| = (5.5 m/s)²/(2(9.8 m/s²)) ≈ 1.543 m . . . . maximum height
For the Data and Observation refer the image attached.
Data Analysis:
Calculate the percentage of the cell cycle spent in each stage.
Number of cells in given stage ÷ total number of cells counted × 100 = % of the cell cycle spent in this stage
Conclusion:
Be sure to answer the following reflection questions in the conclusion of your lab report:
Based on your data, what can you infer about the length of time spent in each stage of the cell cycle?
The most time is used in the cell cycle is in the interphase.
What stages were the longest and shortest? Give a brief explanation of why these stages may have that time period.
The longest phase of the cell cycle is the Interphase. Most of the total time of cell cycle is spent in the Interphase. The reason for this being is that the cell prepares itself for its division, and also in this phase, the necessary protein for the duplication of organelles occurs.
