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snow_tiger [21]
3 years ago
5

How can you divide 58÷0.65

Mathematics
1 answer:
Orlov [11]3 years ago
7 0
You can definitly use a calculator for this 
The answer would be 
<span>89.2307692308
<span><span><span><span><span>What you do is find out how many times 0.65 can go into 58 to get your answer:)

</span></span></span></span></span></span>
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valerie has 20 stuffed animals she wants to store them in plastic bags she estimates she can fit 3 stuffed animals in each bag h
AlekseyPX
She would need about 6 bags because 7*3=21 6+3=18 so about 6 bags
3 0
3 years ago
Need help question #3. Show steps please
Oksana_A [137]

Answer:

B.

Step-by-step explanation:

We are given:

\displaystyle \int \sqrt{x}\Big(9x^3-2\sqrt{x}+\frac{8}{x}\Big)\, dx

And we want to select its equivalent form.

Note that A is not valid. No integration property allows us to separate factors unless that factor is a constant.

We can simply rewrite and then distribute. First, by rewriting:

\displaystyle =\int x^{1/2}\Big(9x^3-2x^{1/2}+8x^{-1}\Big)\, dx

Distribute. Recall exponent properties;

\displaystyle =\int(9x^{3+1/2}-2x^{1/2+1/2}+8x^{-1+1/2})\, dx

Simplify:

\displaystyle=\int9x^{7/2}-2x+8x^{1/2}\, dx

This can then be separated (since its addition/subtraction) and integrated individually.

Hence, our answer is B.

8 0
2 years ago
Gabriel works at an amusement park. He loads 15 new passengers onto the roller coaster every 5/6 of a minute. At what rate does
dem82 [27]

Answer:

12 1/2 or 12.5

Step-by-step explanation:

all you have to do is multiply 15 times 5/6

4 0
3 years ago
What are the solutions to the equation? x^3 - 8x^2 - x + 8 =0
kogti [31]

Answer:

Step-by-step explanation:

x^3 - 8x² - x + 8 =0

x^3 - 8x² - (x - 8 )=0

x²(x-8) - (x-8) = 0

(x-8)(x² -1) =0

x-8 = 0  or x² - 1 = 0

x-8=0 or (x-1)(x+1)=0

x=8 x=1 or x=-1

8 0
3 years ago
Read 2 more answers
Please answer this question now
Kaylis [27]

Answer:

JK=  3 in

Step-by-step explanation:

There is a theorem that says that the angle of a tangent and the radius is of 90°

so we can use the pythagora's theorem

JK^2+JH^2=HK^2\\JK^2+(4)^2=(5)^2\\JK^2+16=25\\JK^2=9\\JK=3

5 0
3 years ago
Read 2 more answers
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