Answer:
Two expressions for the area are;
i) x/3 + 2·y + 6
ii) (1/3) × (x + 6·y + 18)
Step-by-step explanation:
The given dimension of the rectangle are;
The height of the rectangle, h = 1/3
The width of the smallest rectangle, w₁ = x
The width of the med sized rectangle, w₂ = 6·y
The width the large rectangle, w₃ = 18
The area, 'A', of the entire rectangular figure, the big rectangle, can be expressed as follows;
A = A₁ + A₂ + A₃
Where;
A₁ = The area of the smallest rectangle
A₂ = The area of the mid sized rectangle
A₃ = The area of the large rectangle
∴ A = (1/3) × x + (1/3) × 6·y + (1/3) × 18 = x/3 + 2·y + 6
The area of the big rectangle. 'A', can also be found as follows;
A = (1/3) × (x + 6·y + 18)
Therefore, two expressions for the area of the big rectangle are;
x/3 + 2·y + 6 and (1/3) × (x + 6·y + 18).
