What are the zeros of the polynomial function? f(x)=x^3+x^2−9x−9
2 answers:
Answer:
1: x = -1
2: x = 3
3: x = -3
Step-by-step explanation:
f(x)=<u>x^3+x^2</u>−9x−9
f(x)=x^2<u>(</u>x+1) <u>−9x−9</u>
f(x) = x^2<u>(x+1)</u> - 9<u>(x+1)</u>
f(x)= (x+1)<u>(x^2-9)</u>
f(x) =(x+1)(x-3)(x+3)
Answer:

Step-by-step explanation:
The zeros of a function are the values of x when f(x) = 0.

Factor left side of the equation.

Take (x+1) common.

Set factors equal to 0.
First possibility:





Second possibility:


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Answer:
b
Step-by-step explanation:
Answer:
x= -3 1/2x= -3 1/2
Step-by-step explanation: