Question

The volume of sphere is 2254 pi m cubed. what is the surface area to nearest tenth?

Answer 1

$V=2254\pi\ m^3\\\\V=\dfrac{4}{3}\pi r^3\\\\\text{therefore}\\\\\dfrac{4}{3}\pi r^3=2254\pi\ \ \ |:\pi\\\\\dfrac{4}{3}r^3=2254\ \ \ |\cdot\dfrac{3}{4}\\\\r^3=1690.5\to r=\sqrt[3]{1690.5}\to r\approx11.9126\to r\approx11.9$

$S_A=4\pi r^2\to S_A=4\pi\cdot11.9^2=4\pi\cdot141.61=566.44\pi\approx1778.6\ m^2$