20 students.

40% are boys. (40/100)*20 = 0.4 * 20 = 8 boys.
Girls= 20 - 8 = 12 girls.

25% of the boys wear glasses. = (25/100)*8 = 0.25*8 = 2 boys wear glasses.
50% of the girls wear glasses. = (50/100)*12 = 0.50*12 = 6 girls wear glasses.

Total students that wear glasses = 2 + 6 = 8 students.
8 students wear glasses.

7 0

2 years ago

Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (−1, 2) to (1, 2) (a) find a function f

Korvikt [17]

If there is some scalar function $f(x,y)$ such that

$\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j$

then we want to find $f$ such that

$\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)$
$\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C$
$\implies f(x,y)=\dfrac{x^3}3+\dfrac{y^3}3+C$

So the vector field $\mathbf f(x,y)$ is conservative, which means the fundamental theorem applies; the line integral of $\mathbf f$ along any path $\mathcal C$ parameterized by some vector-valued function $\mathbf r(t)$ over $a\le t\le b$ is given by

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))$

In this case,

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(1,2)-f(-1,2)=\dfrac23$

5 0

2 years ago

If 1/64= 4^2 s -1.162s+2 what is the value of s?

antoniya [11.8K]

Answer: Hello brainly student, The answer for this question is that s=1

Step-by-step explanation: Hope this helps you :)

8 0

2 years ago