The answer is D. I’m assuming this is surface area so here’s my explanation:) ok so the area of the triangle is 6 (4x3 divided by 2) and when you add the other triangle that’s 12. Ok so we have 12 so far. Then the area of the bottom rectangle is 24 (3x8). Then the area of the side rectangle is 32 (4x8). THEN the top rectangle’s area is 40 (8x5). When you add the numbers up (12+24+32+40) you get 108! And of course dont forget the cm2. ( centimeters squared ). :) I hope this helps
M is located in Quadrant II, the line BD has a midpoint located in Quadrant II, AD has a midpoint at the origin.
Answer:
C
Step-by-step explanation:
x^2 + 20^2 = 25^2
x^2 + 400 625
x^2 = 225
x = 15
Answer:
76
2 real solutions
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Standard Form: ax² + bx + c = 0
Discriminant: b² - 4ac
- Positive - 2 solutions
- Equal to 0 - 1 solution
- Negative - No solutions/Imaginary
Step-by-step explanation:
<u>Step 1: Define</u>
x² - 6x - 10 = 0
<u>Step 2: Identify Variables</u>
<em>Compare quadratic.</em>
x² - 6x - 10 = 0 ↔ ax² + bx + c = 0
a = 1, b = -6, c = -10
<u>Step 3: Find Discriminant</u>
- Substitute in variables [Discriminant]: (-6)² - 4(1)(-10)
- [Discriminant] Evaluate exponents: 36 - 4(1)(-10)
- [Discriminant] Multiply: 36 + 40
- [Discriminant] Add: 76
This tells us that our quadratic has 2 real solutions.