A polygon with all equal side is called?

Mathematics

1 answer:

disa [49]3 years ago

7 0

The answer would be a equilateral

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Trivia took some fishbowls to a flea market. In the first hour she sold one-third of them and a third more; in the second hour,

a_sh-v [17]

Number of bowls left after 1 hour = x - x/3 - 1/3 = 2x/3 - 1/3

 Number of bowls left after 2 hours = (2x/3 - 1/3) - (2x/3 - 1/3)/2 - 1/2 = 2x/6 - 1/6 - 1/2 = 2x/6 - 4/6 = x/3 - 2/3

keep doing this untill u reach 0 bowls left
and then u'll get ur answer

8 0

3 years ago

please help i will mark brainliest, no spam answers i will report.

vovikov84 [41]

9514 1404 393

Answer:

Step-by-step explanation:

Point E partitions both the x-distance and the y-distance in the ratio 2 : 1. That is, for either the x-coordinates or the y-coordinates, ...

CE : ED = 2 : 1

Try the answers with the x-coordinates.

CE : ED = (1 -(-1)) : (5 - 1) = 2 : 4 . . . . incorrect

CE : ED = (-3 -(-1)) : (5 -(-3)) = -2 : 8 . . . . incorrect

CE : ED = (3 -(-1)) : (5 -3) = 4 : 2 = 2 : 1 . . . . correct

CE : ED = (-1 -(-1)) : (5 -(-1)) = 0 : 6 . . . . incorrect

The only viable choice is (3, 3).

_____

Alternate solution

For a partitioning of m : n, the desired point is ...

E = (n×C +m×D)/(m+n)

For partitioning of 2 : 1, the desired point is ...

E = (1×(-1, -3) + 2×(5, 6))/(2+1) = (-1+10, -3 +12)/3

E = (3, 3)

3 0

3 years ago

66.

Naddik [55]

Answer: 530.66 units²

Step-by-step explanation:

$Area_{(circle)}=\pi r^2\qquad and\qquad r=\dfrac{diameter}{2}\\\\\\\implies Area_{(circle)}=\pi \bigg(\dfrac{diameter}{2}\bigg)^2\\\\\\\text{It is given that the diameter = 26:}\\A=\pi\bigg(\dfrac{26}{2}\bigg)^2\\\\\\.\quad =\pi \cdot 13^2\\\\\\.\quad =169\pi\\\\\\.\quad =\large\boxed{530.66}$