Ask question

Ask question

All categories

4 years ago

7

(3n+2)(2n–3) find the product simplified

2 answers:

nlexa [21]4 years ago

4 0

Answer:

6n2−5n−6

Step-by-step explanation:

Sedbober [7]4 years ago

4 0

Answer:

6n<u>^2</u>-5n-6 (btw <u>"6n^2"</u> means its 6n squared )

Step-by-step explanation:

Use the box Method. (Picture shows the box method)

once your done the simplified answer should be 6n^2-5n-6

You might be interested in

What is the lcm of 8,12,3

Mekhanik [1.2K]

Answer:

24

Step-by-step explanation:

24

The LCM of 3,8,12 3 , 8 , 12 is the result of multiplying all prime factors the greatest number of times they occur in either number. The LCM of 3,8,12 3 , 8 , 12 is 2⋅2⋅2⋅3=24 2 ⋅ 2 ⋅ 2 ⋅ 3 = 24 .

5 0

3 years ago

Two fair number cubes ate rolled. their sum is greater than 10 and one of the number is 6 which of the following best describes

Inga [223]

The answer is B not mutually exclusive

7 0

3 years ago

Can someone help me with question 11

Aleksandr-060686 [28]

Answer:

no i can not

Step-by-step explanation:

6 0

3 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

3 years ago

Suppose the function y = 30,000(1.06)x models the annual profit for a small business x years after 2000. Find the profit at the

goldfiish [28.3K]

From 2000 to 2011, there are 11 years. From the given function, we can calculate the profit for a small business at the end of 2011 by substituting 11 to the x of the given equation.
y = (30,000)(1.06)(11)
y = 349,800
Thus, the profit at the end of 2011 is approximately $349,800.

4 0

4 years ago