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3 years ago

What is the least common multiple of 9, 2, and 12?

2 answers:

8 0

The least common multiple of 9,2 and 12 is 36.

2: 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36
9: 9,18,27,36
12: 12,24,36

Answer: 36

AURORKA [14]3 years ago

6 0

9|3
3|3
1

12|2
6|2
3|3
1

$LCM(2,9,12)=2^2\cdot3^2=4\cdot9=36$

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If each quadrilateral below is a parallelogram,find the missing measures.

zhenek [66]

Answer:

Part 1) $MN=31\ units$

Part 2) $KN=45\ units$

Part 3) m∠K=61°

Part 4) m∠L=119°

Part 5) m∠M=61°

Step-by-step explanation:

we know that

In a parallelogram opposite angles and opposite sides are congruent and consecutive angles are supplementary

Part 1) Find the side MN

we know that

MN≅KL ----> by opposite sides

we have

$KL=31\ units$

therefore

$MN=31\ units$

Part 2) Find the side KN

we know that

KN≅LM ----> by opposite sides

we have

$LM=45\ units$

therefore

$KN=45\ units$

Part 3) Find the measure of angle K

we know that

m∠K+m∠N=180° ----> by consecutive interior angles

we have

m∠N=119°

substitute

m∠K+119°=180°

m∠K=180°-119°

m∠K=61°

Part 4) Find the measure of angle L

we know that

m∠L≅m∠N ----> by opposite angles

we have

m∠N=119°

therefore

m∠L=119°

Part 5) Find the measure of angle M

we know that

m∠M≅m∠K ----> by opposite angles

we have

m∠K=61°

therefore

m∠M=61°

7 0

4 years ago

Help pls ASAP SOLVING QUADRATIC EQUATIONS BY FACTORING

DIA [1.3K]

Answer:

Down, Down, Right, Right, diagonal left, up, right

Step-by-step explanation:

Not gonna do every equation here tho lol

7 0

3 years ago

What is the correct answer?

vovikov84 [41]

Answer:

84 units2

Step-by-step explanation:

First, you multiply 24 *7 = 168

Second, you divide 168 / 2 = 84

Lastly, have a great day!

5 0

3 years ago

A potato chip manufacturer produces bags of potato chips that are supposed to have a net weight of 326 grams. Because the chips

marusya05 [52]

When we take data at work, we always do it over a period of time. To me, just one sample set does not show enough data to come to that conclusion. Also it is one batch of bags. I think you would need to have an average of data from different batches & samples to prove your data is accurate and support your claim.

6 0

3 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

$\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}$

7 0

3 years ago