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Vsevolod [243]
3 years ago
10

Darcy Places 57 Equal Sized Bags Of Rice Onto 3 Shelves At The Fiod Bank the total weight of rice is 54.72 Pounds What Is The We

ight Of Each Bag Of Rice?
Mathematics
1 answer:
Serhud [2]3 years ago
8 0

Weight of each bag is: 0.96 pounds

Step-by-step explanation:

The weight of one bag will be obtained by dividing total weight by the number of bags.

Given

Total bags = 57

Weight of 57 bags = 54.72 pounds

So,

Weight\ of\ one\ bag=\frac{Total\ weight}{Number\ of\ bags}\\=\frac{54.72}{57}\\=0.96\ pounds

Weight of each bag is: 0.96 pounds

Keywords: Division, Conversions

Learn more about division at:

  • brainly.com/question/10435836
  • brainly.com/question/10541435

#LearnwithBrainly

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Evaluate 72 - 12 x 5 – 3(43 = 8)
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Answer:

-31=8

Step-by-step explanation:

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Perry bought 5 nectarines for $4. how many nectarines can amanda buy if she has 16$
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Amanda can buy 20 nectarines with $16
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Calculate the angles of a parallelogram if the sum of the three angles is 310°
Gennadij [26K]

9514 1404 393

Answer:

  adjacent angles are 50° and 130°

Step-by-step explanation:

The sum of all 4 angles in a parallelogram is 360°, so the fourth angle must be ...

  360° -310° = 50°

Adjacent angles are supplementary, so the other two angles must be ...

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The angles in the parallelogram are either 50° or 130°. Adjacent angles are different.

8 0
3 years ago
Pls help and thank you!!
nirvana33 [79]
Your answer is A.

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8 0
3 years ago
In a random sample of 80 teenagers, the average number of texts handled in one day is 50. The 96% confidence interval for the me
Naily [24]

Answer:

Standard deviation of the sample = 17.421

Step-by-step explanation:

We are given that in a random sample of 80 teenagers, the average number of texts handled in one day is 50.

Also, the 96% confidence interval for the mean number of texts handled by teens daily is given as 46 to 54.

So, sample mean, xbar = 50  and   Sample size, n = 80

Let sample standard deviation be s.

96% confidence interval for the mean number of texts,\mu is given by ;

    96% confidence interval for \mu = xbar \pm 2.0537*\frac{s}{\sqrt{n} }

                              [46 , 54]           = 50 \pm 2.0537*\frac{s}{\sqrt{80} }

Since lower bound of confidence interval = 46

So,  46 = 50 - 2.0537*\frac{s}{\sqrt{80} }

       50 - 46 = 2.0537*\frac{s}{\sqrt{80} }

            s = \frac{4*\sqrt{80} }{2.0537} = 17.421

Therefore, standard deviation of the sample is 17.421 .

3 0
4 years ago
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