Lim x->1 (x^2+8x-2)
substitute x =1
= 1^2 +8(1)-2
= 1 +8 -2
= 7
So the limit = 7
Answer: x^2 + y^2 -10y = 0
Step-by-step explanation:
Cartesian coordinates, also called the Rectangular coordinates, isdefined in terms of x and y. So, for the problem θ has to be eliminated or converted using basic foundations that are described by the unit circle and the right triangle trigonometry.
r= 10sin(θ)
Remember that:
x= r × cos(θ)
y= r × sin(θ)
r^2= x^2 + y^2
Multiply both sides of the equation by r. This will give:
r × r = 10r × sin(θ)
r^2 = 10r × sin(θ)
x^2 + y^2= 10r × sin(θ)
Because y= r × sin(θ), we can make a substitution. This will be:
x^2 + y^2= 10y
x^2 + y^2 -10y = 0
The above equation is the Rectangular coordinate equivalent to the given equation.
Answer:
see explanation
Step-by-step explanation:
Inequalities of the type | x | ≤ a always have solutions of the form
- a ≤ x ≤ a
Given
| x - 1 | ≤ 1 then
- 1 ≤ x - 1 ≤ 1 ( add 1 to each of the 3 intervals )
0 ≤ x ≤ 2
Since we require an integer solution then x = 0, 1, 2
Answer:
Simplified: C/2 -4
Step-by-step explanation:
the "/" means fraction
