Answer:
p+5+7=p+12
p/(p+12) ×900=120
900p=120(p+12)
90p=12(p+12)
90p=12p+144
90p-12p=144
78p=144
p=144/78
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Yes it is the solution of the system
Culvert is a tunnel, therefore we can use the volume and area formula of a cylinder.
Circumference is given such as 280 cm and the circumference formula of a circle is C = 2*pi*r
Solving for the radius, we have:
280 = 2*3.14*r
r = 280/2*3.14
r = 44.59 cm
Area of one end:
Area = pi*r²
Area = 3.14 * 44.59²
Area= 6,243.2 cm²
The total area is times two of area since there were two ends in the culvert.
Total area = 6243.2 * 2
Total area = 12,486.32 cm²
Answer:
<u>Step-by-step explanation:</u>
EQ1: x + y = 12 --> x = 12 - y
EQ2: xy = 15
Substitute x = 12-y into EQ2 to solve for y:
(12 - y)y = 15
12y - y² = 15
0 = y² - 12y + 15
↓ ↓ ↓
a=1 b= -12 c=15
Now, let's solve for x:
Lastly, find x² + y² :