Complete the following statement with the number that makes it true.

Approximately what percentage of apple diameters is greater than the 66th percentile? 21. A. 3.4% B. 17% C. 66% D. 34%

astraxan [27]

Answer:

The correct option is D) 34%.

Step-by-step explanation:

Consider the provided information.

If it is given that you scored in the 66th percentile, that means you scored "as well as or better than" 66% of the group.

Here it is given that 66th percentile that means 66% of the data located below the 66th percentile.

That means 100%-66% = 34% of the data located above the 66th percentile,

Thus, the approximately 34% percentage of apple diameters is greater than the 66th percentile.

Therefore, the correct option is D) 34%.

5 0

3 years ago

a distributor wants to make 1000 pounds of trail mix that is 8% raisins. He will use a mix that is 5% raisins and a mix that is

leva [86]

Answer:

200 pounds 20% raisins

800 pounds 5% raisins

Step-by-step explanation:

Let number of 5% be x

and number of 20% be y

x + y = 1000

Also;

5% of x + 20-% of y = 8% of 1000 pounds

= 0.05x + 0.2y = 80

From i , x = 1000-y

0.05(1000-y) + 0.2y = 80

50-0.05y + 0.2y = 80

0.15y = 30

y = 200

x = 1000 - y

= 1000-200 = 800

8 0

3 years ago

Read 2 more answers

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

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$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$