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tankabanditka [31]
3 years ago
6

Tamela's school day is 6 hours. Yesterday, she had a doctor appointment and she missed 1/6 of her school day. How many school ho

urs did she miss
during her doctor appointment? Express your answer in simplest form.
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0

Answer:

1 hour

Step-by-step explanation:

Equation: 6 hours × 1/6 hours = 1 hour

If there are 6 hours and Tamela missed 1/6, that means she missed 1 hour of school.

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Slope is -5/3
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3 years ago
Given: an=3+an−1 and a1=5<br><br> What is the explicit rule for the arithmetic sequence?
Flura [38]

The explicit rule for the arithmetic sequence for the sequence is a(n) = 3n + 2.

<h3>What is a sequence?</h3>

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

We have given:

\rm a_n=3+a_n_-_1 and

\rm a_1=5

\rm a_n-a_n_-_1= 3

The above expression represents the common ratio:

d = 3

First term:

a = 5

The explicit rule for the arithmetic sequence:

a(n) = 5 + (n - 1)3

a(n) = 3n + 2

Thus, the explicit rule for the arithmetic sequence for the sequence is a(n) = 3n + 2.

Learn more about the sequence here:

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3 0
2 years ago
Need help due in 25 minutes
masha68 [24]

Answer:

Area = 400  Perimeter = 80

Step-by-step explanation:

aree = 400

side = sqrt of 400 = 20

perimeter = 4*20 = 80

7 0
3 years ago
A consumer group is interested in estimating the proportion of packages of ground beef sold at a particular store that have an a
snow_tiger [21]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We assume that the estimated proportion for this case is \hat p =0.5 since we don't have prior information.

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

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3 years ago
If you answer this question CORRECTLY, you will get a free $25 Dollar Amazon Gift Card. (Also will be given brainliest)
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

8 0
3 years ago
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