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4 years ago

A triangle with one obtuse angle must also have two acute angles.a. trueb. false

1 answer:

7 0

(a) True

Because the sum of the angles in a triangle is 180°

Obtuse angle = angle greater than 90°.

180° - Obtuse angle = less than 90°

So there cannot be another obtuse angles, therefore both the other angles will be acute.

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Step-by-step explanation:

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3 years ago

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Triss [41]

Answer:

$\text{The roots of }3x^2+5x-8=0\text{ are }x=1,\frac{-8}{3}$

Step-by-step explanation:

$\text{Part A: Given a quadratic equation }3x^2-15x+20=0$

$\text{Comparing above equation with }ax^2+bx+c=0$

a=3, b=-15, c=20

Discriminant can be calculated as

$D=b^2-4ac$

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The roots are not real i.e these are imaginary

$\text{Part B: Given a quadratic equation }3x^2+5x-8=0$

$\text{Comparing above equation with }ax^2+bx+c=0$

a=3, b=5, c=-8

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$D=b^2-4ac$

$D=(5)^2-4(3)(-8)=25+96=121>0$

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By quadratic formula method

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$x=\frac{-b\pm\sqrt{D}}{2a}$

$x=\frac{-5)\pm \sqrt{121}}{2(3)}=\frac{-5\pm 11}{6}$

$x=1,\frac{-8}{3}$

which are required roots.

I choose this method because I can get the solutions directly by substituting the values in formula, and I don't have to guess the possible solutions.

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