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timama [110]
3 years ago
15

Convert 84% percent to a fraction in simplest form.

Mathematics
2 answers:
Svetlanka [38]3 years ago
8 0
84/100 which would then be 42/50 which will then be 21/25
zimovet [89]3 years ago
5 0

To write a percent as a fraction in lowest terms, first remember that a percent is a ratio that compares a number to 100. In this case, 84% can be written as the ratio 84 to 100 or \frac{84}{100}. Notice however that \frac{84}{100} is not in lowest terms. So, we need to divide the numerator and the denominator by 4 which gives us \frac{21}{25}.

Therefore, 84% can be written as the fraction \frac{21}{25}, which is in lowest terms.

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Assume that​ women's heights are normally distributed with a mean given by mu equals 62.5 in​,and a standard deviation given by
Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with  

\mu = 62.5 in

\sigma = 2.2 in

the normal probability density function is given by  

f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}, then

(a) P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx = 0.5899

   (in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking P(\bar{X} < 63) where n = 37. \bar{X} is normally distributed with mean 62.5 in and standard deviation 2.2/\sqrt{37}. So, the probability density function is given by

g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}, and

P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0
3 years ago
IM RELLY DONE I DONT UNDERSTAND THIS <br>And answer is not (-5.-2) e.t.c<br>PLS HELP​
zhenek [66]

Answer: -5, 1: -5, 2: -8, 1

Step-by-step explanation: Just flip it on the other side

7 0
2 years ago
Read 2 more answers
How to solve derivative of (sin3x)/x using first principle ​
Leona [35]

\dfrac{d}{dx}(\dfrac{\sin(3x)}{x})

First we must apply the Quotient rule that states,

(\dfrac{f}{g})'=\dfrac{f'g-g'f}{g^2}

This means that our derivative becomes,

\dfrac{\dfrac{d}{dx}(\sin(3x))x-\dfrac{d}{dx}(x)\sin(3x)}{x^2}

Now we need to calculate \dfrac{d}{dx}(\sin(3x)) and \dfrac{d}{dx}(x)

\dfrac{d}{dx}(\sin(3x))=\cos(3x)\cdot3

\dfrac{d}{dx}(x)=1

From here the new equation looks like,

\dfrac{3x\cos(3x)-\sin(3x)}{x^2}

And that is the final result.

Hope this helps.

r3t40

7 0
2 years ago
Read 2 more answers
Solve for h in A = ½ ah - ½ bh. Solve for h in A = ½ ah - ½ bh .​
pantera1 [17]

Answer:

h = A / ( 1/2 a - 1/2 b)

Step-by-step explanation:

A = ½ ah - ½ bh

Factor out an h

A = h( 1/2 a - 1/2 b)

Divide each side by ( 1/2 a - 1/2 b)

A / ( 1/2 a - 1/2 b) = h ( 1/2 a - 1/2 b)/ ( 1/2 a - 1/2 b)

A / ( 1/2 a - 1/2 b) = h

h = A / ( 1/2 a - 1/2 b)

7 0
2 years ago
If someone picks you as the brainiest or wutever, wut does that do?
olasank [31]
I think it just gives the other person 3 points but idk
6 0
3 years ago
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