Answer:
IS A
PLEASE MARK ME AS BRAINLIEST
Step-by-step explanation:
<span>30 hours
For this problem, going to assume that the actual flow rate for both pipes is constant for the entire duration of either filling or emptying the pool. The pipe to fill the pool I'll consider to have a value of 1/12 while the drain that empties the pool will have a value of 1/20. With those values, the equation that expresses how many hour it will take to fill the pool while the drain is open becomes:
X(1/12 - 1/20) = 1
Now solve for X
X(5/60 - 3/60) = 1
X(2/60) = 1
X(1/30) = 1
X/30 = 1
X = 30
To check the answer, let's see how much water would have been added over 30 hours.
30/12 = 2.5
So 2 and a half pools worth of water would have been added. Now how much would be removed?
30/20 = 1.5
And 1 and half pools worth would have been removed. So the amount left in the pool is
2.5 - 1.5 = 1
And that's exactly the amount needed.</span>
Answer:
f(3) = 15. Correct: D)
Explanation:
<u>Numeric Value of a Function</u>
The value of a function f(x) when x = a is calculated by replacing the x for a. We have the function:
It is required to find f(3), or the numeric value of f when x=3. Replace x for 3
A) Incorrect. f(3) is not 7
B) Incorrect. f(3) is not 10
C) Incorrect. f(3) is not 9
D) Correct. f(3) =15 as found above.
Answer:
Bill will earn more interest
He will earn $ 20,448.67 from his investment
Step-by-step explanation:
Firstly let us calculate Jim's earnings based on simple interest
A = P(1 + rt)
Calculation:
First, converting R percent to r
a decimal
r = R/100 = 3.5%/100 = 0.035 per year.
Solving our equation:
A = 15000(1 + (0.035 × 25)) = 28125
A = $28,125.00
The total amount accrued, principal plus interest, from simple interest on a principal of $15,000.00 at a rate of 3.5% per year for 25 years is $28,125.00 for Jim
Now let's us calculate bill's investment based on compound interest
Equation
A = P(1 + r)^t
A=15000(1+0.035)^25
A=15000(1.035)^25
A=15000*2.36324498427
A = $ 35,448.67
We see that Bill will earn
$ 20,448.67 from his investment
