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Serggg [28]
3 years ago
11

What is the Standard Form of (7x1)+[6x[tex]What is the Standard Form for (7x1)+[6x\frac{1}{1,000}?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

7374

Step-by-step explanation:

I just know that's the right answer

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Help asap!!!!!!!!!!!
svlad2 [7]

Answer:

The answer to your question is:

Step-by-step explanation:

12.-

                x² - 6x = 5

                x² - 6x + (3)² = 5 + (3)²

               x² - 6x + 9 = 5 + 9

               (x - 3)² = 14

13.-           x² - 6x = 12

               x² - 6x + (3)² = 12 + (3)²

               x² - 6x + 9 = 12 + 9

              (x - 3)² = 21

              x - 3 = ±√21

             x1 = √21 + 3                     x2 = -√21 + 3

               x1 = 7.58                           x2 = -1.58

14.-           2x² - 24x = - 20            Divide by 2

                x² - 12 x = -10

               x² - 12x + (6)² = - 10 + (6)²

               x² - 12x + 36 = - 10 + 36

              ( x - 6) ² = 26

               x - 6 = ±√26

x1 = √26 + 6                                 x2 = -√26 + 6

x1 = 11.1                                          x2 = 0.9

3 0
3 years ago
if sec theta equals negative 5/3, such that 180° <thata<270° then determine what is tan theta ?
Svetllana [295]
I hope this makes sense, if not please feel free to let me know and I'll explain it. 

4 0
3 years ago
Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

3 0
2 years ago
What is the solution to-5x=-75​
Furkat [3]

Answer:

-15

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Find the value of z.
AVprozaik [17]

Answer:

  z = 110°

Step-by-step explanation:

Angles z and the one marked 70° form an linear pair, hence are supplementary.

  z = 180° -70° = 110°

<h3>Angles where chords cross</h3>

The angle made by two chords is half the sum of the arcs intercepted by those chords. Here, that means ...

  70° = 1/2(60° +x)   ⇒   x = 140° -60° = 80°

The arc w completes the circle of 360°, so we have ...

  w +x +79° +60° = 360°   ⇒   w = 360° -219° = 141°

Finally, z is the average of w and 79°:

  z = (w +79°)/2 = (141° +79°)/2 = 110° . . . as above

8 0
1 year ago
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