Step-by-step explanation:
9. log(2)=a, log(3)=b, then log(36)=______
log(36) = log(6*6) = log(6) + log(6)
log(36)= log(6) + log(6)
log(36) = log(3*2) + log(3*2)
log(36) = (log(3) + log(2)) + (log(3) + log(2))
log(36) = (a + b) + (b + a)
log(36) = a + b + b + a
log(36) = 2a + 2b
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.
1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46
So we have two possibilities: either #2 or #4. Find least possible pair of integers.
x= first integer
x+1= second integer
x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5
Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.
Hope this helps! :)
Answer:
Question one: Zero slope
Question two: 
Step-by-step explanation:
Given the following questions:
<u>Question one:
</u>The following line is what you call a "zero slope." Zero slopes are lines that are neither decreasing or increasing and remain at a constant or just a straight line.
Question two:
Point A = (-2, -3) = (x1, y1)
Point B = (2, -3) = (x2, y2)
Using the formula for slope or rise over run we will solve and find the slope of this line.
The slope of this line is "0/4."
Hope this helps.
I think you would use the Pythagorean Theorem to solve this, as a square cut across diagonally creates two isocele triangles. Since the longest side is 20 m, this value would be imputed into c^2.
a^2 + b^2 = c^2
a^2 + a^2 = 20^2
2a^2 = 400
2a^2/2 = 400/2
a^2 = 200
a = 14.14
Thus, each sides of the playground are 14.14 meters long.
