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Bumek [7]
3 years ago
8

You don’t know how important this is Please help me!!

Mathematics
1 answer:
Natali5045456 [20]3 years ago
7 0

Answer:

f(x)=\frac{7}{5}x-\frac{6}{5}

Step-by-step explanation:

First put 7x-5y=6 into slope intercept form

y=\frac{7}{5}x-\frac{6}{5}

Then put it into f(x) form

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Find the measure of the remote exterior angle. <br> m∠x=(5n−19)°<br> m∠y=(n+7)°<br> m∠z=(144−6n)°
navik [9.2K]

Answer:

66°

Step-by-step explanation:

An exterior angle of a triangle is equal to the sum of the opposite interior angles.

x + y = z

5n − 19 + n + 7 = 144 − 6n

6n − 12 = 144 − 6n

12n = 156

n = 13

m∠z = (144−6n)°

m∠z = (144−6×13)°

m∠z = 66°

7 0
3 years ago
What is the value of the y-coordinate where this line crosses the y-axis? (7, 17) (3,9) ​
Mekhanik [1.2K]

Answer:

3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How many square inches are in 60 square feet?
antoniya [11.8K]

Answer:

8640

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Drone INC. owns four 3D printers (D1, D2, D3, D4) that print all their Drone parts. Sometimes errors in printing occur. We know
USPshnik [31]

Answer:

Step-by-step explanation:

Hello!

There are 4 3D printers available to print drone parts, then be "Di" the event that the printer i printed the drone part (∀ i= 1,2,3,4), and the probability of a randomly selected par being print by one of them is:

D1 ⇒ P(D1)= 0.15

D2 ⇒ P(D2)= 0.25

D3 ⇒ P(D3)= 0.40

D4 ⇒ P(D4)= 0.20

Additionally, there is a chance that these printers will print defective parts. Be "Ei" represent the error rate of each print (∀ i= 1,2,3,4) then:

P(E1)= 0.01

P(E2)= 0.02

P(E3)= 0.01

P(E4)= 0.02

Ei is then the event that "the piece was printed by Di" and "the piece is defective".

You need to determine the probability of randomly selecting a defective part printed by each one of these printers, i.e. you need to find the probability of the part being printed by the i printer given that is defective, symbolically: P(DiIE)

Where "E" represents the event "the piece is defective" and its probability represents the total error rate of the production line:

P(E)= P(E1)+P(E2)+P(E3)+P(E4)= 0.01+0.02+0.01+0.02= 0.06

This is a conditional probability and you can calculate it as:

P(A/B)= \frac{P(AnB)}{P(B)}

To reach the asked probability, first, you need to calculate the probability of the intersection between the two events, that is, the probability of the piece being printed by the Di printer and being defective Ei.

P(D1∩E)= P(E1)= 0.01

P(D2∩E)= P(E2)= 0.02

P(D3∩E)= P(E3)= 0.01

P(D4∩E)= P(E4)= 0.02

Now you can calculate the probability of the piece bein printed by each printer given that it is defective:

P(D1/E)= \frac{P(E1)}{P(E)} = \frac{0.01}{0.06}= 0.17

P(D2/E)= \frac{P(E2)}{P(E)} = \frac{0.02}{0.06}= 0.33

P(D3/E)= \frac{P(E3)}{P(E)} = \frac{0.01}{0.06}= 0.17

P(D4/E)= \frac{P(E4)}{P(E)} = \frac{0.02}{0.06}= 0.33

P(D2)= 0.25 and P(D2/E)= 0.33 ⇒ The prior probability of D2 is smaller than the posterior probability.

The fact that P(D2) ≠ P(D2/E) means that both events are nor independent and the occurrence of the piece bein defective modifies the probability of it being printed by the second printer (D2)

I hope this helps!

8 0
3 years ago
A man gets an invoice for ​$460 with terms 4/10, ​1/15, n/30. How much would he pay 6 days after the invoice​ date?
7nadin3 [17]

Answer:

$441.60

Step-by-step explanation:

Invoice amount: $460

Term 4/10= 4% discount if paid early within the first 10 days of the invoice date

Amount due: $441.60

Discount amount: $18.40

Invoice amount: $460

Term: 1/15= 1% discount if paid early within the first 15 days of the invoice date

Amount due: $455.40

Discount amount: $4.60

Invoice amount: $460

Term: n/30= no discount if paid on or after the 30 days from the invoice date

Amount due: $460

Discount amount: $0

3 0
2 years ago
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