Answer:
a = 1 and b = - 10
Step-by-step explanation:
Expand the right side of the identity
x(ax² - 3x + b) - 3(ax² - 3x + b)
= ax³ - 3x² + bx - 3ax² + 9x - 3b
= ax³ - x²(3 + 3a) + x(b + 9) - 3b
Equate the coefficients of like terms on both sides of the identity
x³ terms → ax³ with x³ ⇒ a = 1
x terms → - x with (b + 9)x ⇒ b + 9 = - 1 ⇒ b = - 10
Answer: 28/45
Step-by-step explanation:
Answer:
hey my friend please come over to spend the Christmas holidays with me and my family this year. If you are afraid of your dad it's ok I'll ask my mom to call him and ask him
We will form the equations for this problem:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
z = ? Monthly administration fee is notated with z, and that is the this problem's question.
Number of kilowatt hours of electricity used are numbers 1100 and 1500 respectively.
Cost per kilowatt hour is notated with y, but its value is not asked in this math problem, but we can calculate it anyway.
The problem becomes two equations with two unknowns, it is a system, and can be solved with method of replacement:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
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(1) z = 113 - 1100*y [insert value of z (right side) into (2) equation instead of z]:
(2) 1500*y + (113 - 1100*y) = 153
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(1) z = 113 - 1100*y
(2) 1500*y + 113 - 1100*y = 153
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(1) z = 113 - 1100*y
(2) 400*y + 113 = 153
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(1) z = 113 - 1100*y
(2) 400*y = 153 - 113
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(1) z = 113 - 1100*y
(2) 400*y = 40
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(1) z = 113 - 1100*y
(2) y = 40/400
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(1) z = 113 - 1100*y
(2) y = 1/10
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if we insert the obtained value of y into (1) equation, we get the value of z:
(1) z = 113 - 1100*(1/10)
(1) z = 113 - 110
(1) z = 3 dollars is the monthly fee.
Using the inequality
2.50x + 3.50y ≤ 30
substituting y with the number of cheeseburgers sold
2.5x + 3.5(4) ≤ 30
x = 6.4
The maximum number of hamburgers he can sell is 6
