<span>que debería haber escrito sólo el problema para nosotros tal vez podríamos haber ayudado a continuación .</span>
is the expression that includes an exponent and has a value of 8
<em><u>Solution:</u></em>
Given that, Use the number 8, 6, and 2 and one operation to write an expression that includes an exponent and has a value of 8
We have to use each number only once
Given numbers are 8, 6, 2
Our expression should include exponent and the result should be 8
Among 6 and 2 we can use 2 for exponent
Raise 2 to power of 1
<em><u>The expression becomes:</u></em>
Here we have used one operation, that is addition
Verifying the expression
Thus the required expression is found
First one:
you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so
when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)
-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m
add
-10m-13m+2m^4-20m^4
-23m-18m^4
second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms
(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8
It is rounded down to 151.
Answer:
2x + y = 7
x=7/2
y=7
Step-by-step explanation:
to find y itercept =0
to find x intercept=0
