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koban [17]
3 years ago
5

What is the slope of the line that contains the points (0,7) and (8,-3)

Mathematics
2 answers:
Novay_Z [31]3 years ago
4 0
Slope=\frac{change in y}{change in x}
slope m= \frac{7--3}{0-8}
m=\frac{10}{-8}
Umnica [9.8K]3 years ago
4 0

I got chu


A. -5/4 (make sure you check if it’s the right one they change the order)

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Sally is analyzing a circle, y2 + x2 = 9, and a linear function g(x). Will they intersect?
Mamont248 [21]
This ones kinda hard I'm not really sure, but looking at the table, when f(x) = 1, g(x) = 1. So therefore it is yes, and Im guessing you know the negative and positive x coordinates/zero thing, so I think you should be correct. Sorry if this is wrong, not too sure, but hopefully it gives you a better idea.
4 0
3 years ago
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7100 dollars is placed in an account with an annual interest rate of 7.75%. How much will be in the account after 30 years, to t
Evgen [1.6K]

Answer:

$66,646.40 is the answer

Step-by-step explanation:

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3 years ago
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Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f
GalinKa [24]

Answer:

\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in \mathbb{R}.

\\f(x)=(x^2+16)(x^2-2x-15)

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}

And we can write in \mathbb{C}

f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0
3 years ago
Write the equation for a line perpendicular to a line passing through points (-1,2) and (1,-8)
soldi70 [24.7K]

Answer:

Step-by-step explanation:

Slope m = (-8-2)/(1+1)=-10/2 = -5

Perpendicular slope-1/m = -1/-5 = 1/5

Equation of a line with perpendicular slope is

y-y1=(-1/m)(x-x1)

y - 2 = (1/5)(x+1)

y =2 +(1/5)(x+1)

3 0
2 years ago
6. If ABCD is a square and AD = 11. find each missing value.
MAVERICK [17]

Answer:

All sides will be 11 and all angles will be 90 degrees.

Step-by-step explanation:

As all sides of square are equal. And all angles are right angled.

Hope it helped!!

3 0
3 years ago
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