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Alona [7]
3 years ago
10

The amount of fuel in a tractor's fuel tank is changing according to the equation y=−3x+40 , where x = time in hours and y = amo

unt in gallons.
What is the rate of change described by the equation? Explain the meaning of the rate of change in this situation.
Mathematics
2 answers:
Alenkasestr [34]3 years ago
7 0

Answer:

The rate of change is "-3". Which means the rate at which the tractor uses fuel.

Step-by-step explanation:

The equation describes a line and any line follows the equation:

y = m*x + c

Where "m" is the rate of change and "c" is the shift on the line. Comparing the equation for the fuel and the equation from the line, the rate of change must be "-3". The rate of change in this context describes the speed at which the tractor uses fuel, at a rate of 3 gallons per hour.

brilliants [131]3 years ago
3 0

Answer:

-3

Step-by-step explanation:

i think i used my head to the problem to think of it

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The average score of all golfers for a particular course has a mean of 71 and a standard deviation of 3. Suppose 36 golfers play
Zielflug [23.3K]

Answer:

.0228

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 71, \sigma = 3, n = 36, s = \frac{3}{\sqrt{36}} = 0.5

Find the probability that the average score of the 36 golfers exceeded 72.

This is 1 subtracted by the pvalue of Z when X = 72. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{72 - 71}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

7 0
3 years ago
How many solutions?
MakcuM [25]

Answer:

0 solutions

Step-by-step explanation:

These system of equations are inconsistent (parallel to each other) which means that there are no solutions to this system.

7 0
3 years ago
Read 2 more answers
If the relation is a function, list the domain and range. If the relation is not a function, choose "not a function".
Ber [7]
Function...
Domain:9,8,7,-5
Range:1,-3,5,3
3 0
4 years ago
Reid and Maria both play soccer. This season, Reid scored 4 less than twice the number of goals that Maria scored. The differenc
kap26 [50]

Answer:

I think its D

Step-by-step explanation:

Because its asking for 4 less then twice the number 6 so it would be 10 and 16 btw im so sorry if im wrong

7 0
3 years ago
A mixture of purple paint contains 6 teaspoons of red paint and 15 teaspoons of blue paint. To make the same shade using the 35
andrew-mc [135]

Answer:

87.5 teaspoons

Step-by-step explanation:

Given that a mixture of purple paint contains 6 teaspoons of red paint and 15 teaspoons of blue paint.

So, Purple paint : Blue paint =  6 :15

To make the same shade the ratio of purple and blue paint must be the same.

In the new mixture, the amount of purple paint =35 teaspoon.

let the amount of red paint =x teaspoon.

So, in the new mixture,

Purple paint : Blue paint =  35 : x

So, to make the same shade, the ratio of purple and red paint must be the same, i.e

35 : x =  6 :15

\Rightarrow \frac {35}{x}=\frac{6}{15}

\Rightarrow x={35\times15}{6}=87.5

Hence, 87.5 teaspoons of red paint required to mix with 35 teaspoons of purple paint to make the same shade.

6 0
3 years ago
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