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Shkiper50 [21]
3 years ago
7

A buffer is prepared by adding 18.0 g of sodium acetate (ch3coona to 510 ml of a 0.160 m acetic acid (ch3cooh solution. determin

e the buffer
Chemistry
1 answer:
Nutka1998 [239]3 years ago
4 0
Given:

mass of sodium acetate = 18.0 grams
volume of acetic acid = 510 ml
concentration of acetic acid = 0.160 M

Solve for the ph of the buffer:

pH = pKa + log [salt]/[acid]

pKa of acetic acid = 4.76
M of sodium acetate = 82g/mol
pH = 4.76 + log [18g/82g/mol] / [0.160M*(510/1000)]
pH = 5.19


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