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Anastaziya [24]
3 years ago
5

How many grams of H2 are needed to produce 13.33g of NH3?

Chemistry
1 answer:
Zanzabum3 years ago
3 0

The reaction to form NH3 is : N2 + 3H2-> 2NH3 12,33g NH3 is 12,33/17,03=0,3 =0,724 moles of NH3 moles NH3. So you need 1,5*0,724 = 1,086 moles H2 1,086*2,016 = 2,189 g of H2 is needed ro form 12,33 g NH3

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Answer:

39.3%

Explanation:

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We must first determine the limiting reactant, the limiting reactant is the reactant that yields the least number of moles of products. The question explicitly says that H2SO4 is in excess so CaF2 is the limiting reactant hence:

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Number of moles reacted= mass/molar mass

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% yield of HF= actual yield/ theoretical yield ×100

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