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777dan777 [17]
3 years ago
12

-4.5 + 4.4 + -6.7 + 6.8

Mathematics
2 answers:
mihalych1998 [28]3 years ago
8 0

Answer:

the answer to this is 0

sleet_krkn [62]3 years ago
8 0

Answer:

0

Step-by-step explanation:

The equation will be -4.5 + 4.4 - 6.7 +6.8 because the positive and negative will make a negative and so you solve the equation. Combine positives(4.4 and 6.8) and should get 11.2 then combine the negatives and get -11.2 and then you subtract the two numbers and get 0.

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What is the vertex of the quadratic function f(c)=(x-8)(x-2)
lisov135 [29]

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3 years ago
Please help I'm bad at math i don't understand
dybincka [34]

Answer:

a) Vertex is at (-3, -1)

b) y-intercept is at (0,8)

c) x intercept is at (-4,0) and (-2,0)

d) x=-3

Step-by-step explanation:

The vertex of a parabola is the lowest or highest point, implying that all points are reflected across it. It's the only y value that doesn't have a corresponding pair.

For example, -1 and 1, -3 and 3, and so on.

The vertex is at (-3,-1) because it is the sole point without a corresponding y value (-3,-1)

The y-intercept is where the parabola meets the y axis or when the x value equals 0. To determine the y-intercept, simply find when x = 0.

intercept y: (0,8)

The x-intercepts are the same as the y-intercepts; you must determine where the parabola crosses the x-axis or when y = 0.

x intercept 1:(-4,0)

x intercept 2: (-2,0)

The axis of symmetry is also the x coordinate of the vertex which is 3 so

x = 3

7 0
3 years ago
Does the equation y = (0.9)x represents exponential growth or decay?Answer
Fittoniya [83]
U mean y = 0.9^x ...?
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its exponential decay...
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because.. y = (1/e)^x is exponential decay...
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(1/e) < 1

4 0
4 years ago
A box with a square base and open top must have a volume of 157216 cm3. We wish to find the dimensions of the box that minimize
shepuryov [24]

Answer:

  • Base Length of 68cm
  • Height of 34 cm.

Step-by-step explanation:

Given a box with a square base and an open top which must have a volume of 157216 cubic centimetre. We want to minimize the amount of material used.

Step 1:

Let the side length of the base =x

Let the height of the box =h

Since the box has a square base

Volume =x^2h=157216

h=\dfrac{157216}{x^2}

Surface Area of the box = Base Area + Area of 4 sides

A(x,h)=x^2+4xh\\$Substitute h=\dfrac{157216}{x^2}\\A(x)=x^2+4x\left(\dfrac{157216}{x^2}\right)\\A(x)=\dfrac{x^3+628864}{x}

Step 2: Find the derivative of A(x)

If\:A(x)=\dfrac{x^3+628864}{x}\\A'(x)=\dfrac{2x^3-628864}{x^2}

Step 3: Set A'(x)=0 and solve for x

A'(x)=\dfrac{2x^3-628864}{x^2}=0\\2x^3-628864=0\\2x^3=628864\\x^3=314432\\x=\sqrt[3]{314432}\\ x=68

Step 4: Verify that x=68 is a minimum value

We use the second derivative test

If\:A(x)=\dfrac{x^3+628864}{x}\\A''(x)=\dfrac{2x^3+1257728}{x^3}\\$When x=68\\A''(x)=6

Since the second derivative is positive at x=68, then it is a minimum point.

Recall:

h=\dfrac{157216}{x^2}\\h=\dfrac{157216}{68^2}=34

Therefore, the dimensions that minimizes the box surface area are:

  • Base Length of 68cm
  • Height of 34 cm.
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