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rewona [7]
4 years ago
6

What is two filths plus one eighth

Mathematics
1 answer:
pantera1 [17]4 years ago
4 0

Answer: 21/40

Step-by-step explanation:

25+18=?The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(2/5, 1/8) = 40

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(25×88)+(18×55)=?

Complete the multiplication and the equation becomes

1640+540=?

The two fractions now have like denominators so you can add the numerators.

Then:

16+540=2140

This fraction cannot be reduced.

Therefore:

25+18=2140

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Height of Dutch Men. Males in the Netherlands are the tallest, on average, in the world with an average height of 183 centimeter
trapecia [35]

Answer:

a) P(X

P(z

b) P(X>195) =P(Z>\frac{195-183}{10.5})=P(Z>1.143)

P(z>1.143)=1-P(Z

c) P(173

P(-0.953

P(-0.953

d) P(\bar X >190)=P(Z>\frac{190-183}{\frac{10.5}{\sqrt{1000}}}=21.08)

And using a calculator, excel ir the normal standard table we have that:

P(Z>21.08)=1-P(Z

So for this case we expect anyone with a heigth higher than 190 cm in a random sample of 1000.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(183,10.5)  

Where \mu=183 and \sigma=10.5

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability with the normal standard table or with excel:

P(z

Part b

P(X>195)

P(X>195) =P(Z>\frac{195-183}{10.5})=P(Z>1.143)

And we can find this probability with the normal standard table or with excel: using the complement rule

P(z>1.143)=1-P(Z

Part c

P(173

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(173And we can find this probability on this way:

P(-0.953

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.953Part d

Since the distributiion for X is normal then the distribution for the sample mean is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we eant this probability:

P(\bar X >190)=P(Z>\frac{190-183}{\frac{10.5}{\sqrt{1000}}}=21.08)

And using a calculator, excel ir the normal standard table we have that:

P(Z>21.08)=1-P(Z

So for this case we expect anyone with a heigth higher than 190 cm in a random sample of 1000.

3 0
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20. Determine the rate of change for the following equation on the given interval.
BigorU [14]
-2<x<3   | *2
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3<10<13

The answer is C

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3 years ago
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Answer:

x+y=5a

5a is added to b which is the sum of x and y multiplied by 3. That is, b=x+y×3=5a×3=15a

Since, 5a is added to b= 5a+15a=20a,

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Can i have some help
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Answer:

B vangkee

Step-by-step explanation:

saya anak Wibu vangke sekaligus K pop vangkee

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