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4 years ago

The first number in a multiplication problem is called the

1 answer:

6 0

Numbers in multiplication are called factors. In algebra, the first number is called coefficient (e.g. 2 in 2x). It is also called multiplier.

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What is 3/4 -7/10 -3/4 and 8/10 In order from least to greatest

zaharov [31]

-3/4, -7/10, 3/4, 8/10 is least to greatest

3 0

3 years ago

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The median number of goals scored by 7 players in a certain soccer season is 5. The range of the number of goals scored by those

Readme [11.4K]

greatest # of goals cannot be 10, false

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3 years ago

what are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x- pi) from x = 0 to x= 2 pi?

julsineya [31]

Answer:

$\frac{\pi }{2}$ and $\frac{3\pi }{2}$

Step-by-step explanation:

To find the max points we need to take the derivative of the function and then find the critical values.

First we take the derivative:

$f(x) = 4cos(2x-\pi )\\f'(x)=-4sin(2x-\pi )(2)\\f'(x)=-8sin(2x-\pi )\\$

Now we need to find when f'(x)=0 to find the critical values.

$0=-8sin(2x-\pi )\\0=sin(2x-\pi )\\sin^{-1}0=2x-\pi \\0=2x-\pi \\\pi =2x\\\frac{\pi }{2} =x$

The critical values will be

$\frac{\pi }{2} n$ for any integer n

between 0 and 2 pi, the critical values will be

$0, \frac{\pi }{2} ,\pi ,\frac{3\pi }{2},2\pi$

We can determine if these are minimums or maximums by using the second derivative test.

So we need to take the second derivative;

$f'(x)=-8sin(2x-\pi )\\f''(x) = -8cos(2x-\pi )(2)\\f''(x)=-16cos(2x-\pi)$

We need to see if the second derivative is positive or negative to determine if it is a max or min.

$f''(0) = 16\\f''(\frac{\pi}{2})=-16\\f''(\pi )=16\\f''(\frac{2\pi}{3}) = -16\\$

Since the second derivative is negative at

$\frac{\pi }{2}$ and $\frac{3\pi }{2}$

we know both of those are the x-values of maximums.

5 0

4 years ago

I need help asap im timed

Iteru [2.4K]

Answer:-

Refer to attachment for the required solution.

8 0

3 years ago

Read 2 more answers

John, Johan, and Jonathan collect postage stamps. Johan and Jonathan have the same number of stamps. Two times Johan’s collectio

kati45 [8]

Let d = number of stamps from John (4 letters, d is 4th letter, etc)
Let e = number of stamps from Johan 
Let h = number of stamps from Jonathan 

Johan and Jonathan have the same number of stamps, so: 

e = h 

2 times Johan's collection is 11 less than 5 times John's collection, so: 

2e = 5d - 11 

3 times Jonathan's collection is 3 less than 7 times John's collection,so: 

3h = 7d - 3 

Now we have three equations and three unknowns. You're asked for the number of stamps in John's collection, so you want the value to variable "d". 

Since e = h, we can substitute "h" for "e" in the second equation. 

2h = 5d - 11 
3h = 7d - 3 

now we have two equations and two unknowns. I'll use elimination, starting with multiplying the first equation by -3 and the second one by 2. 

-6h = -15d + 33 
6h = 14d - 6 

now add both together and you have an equation with one unknown remaining: 

0 = -d + 27 
d = 27 

So your answer is 27 stamps. If you want to know how many stamps the others have, you can work back and solve for e and h.

7 0

4 years ago

Read 2 more answers