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Papessa [141]
3 years ago
9

1.Write this sentence as an equation.Do not solve it.

Mathematics
1 answer:
Ivahew [28]3 years ago
7 0

Problem 1

x = some unknown number

3x = three times a number

3x-7 = difference of three times a number and seven

2(3x-7) = two times the difference of three times a number and seven

2(3x-7) = x

The last equation is formed because the expression we built up is equal to the original number in question

<h3>Answer:  2(3x-7) = x</h3>

===========================================================

Problem 2

Use the distribution rule to get

3(2x+4)-2x

3*2x+3*4-2x

6x+12-2x

From here, we combine like terms. That means we combine the 6x and -2x to get 4x

So 6x+12-2x simplifies to 4x+12 and not 16x

How did she get 16x? Possibly because she mistakenly thought she could add 4x to 12 to get 16x. This only works if the 12 had x attached to it.

In other words, this is valid:  4x+12x = 16x but this is not 4x+12 = 16x

===========================================================

Problem 3

L = length = horizontal dimension = (d+15) ft

W = width = vertical dimension = (d-3) ft

P = perimeter of the rectangle = 108 ft

P = 2(L+W)

108 = 2(d+15+d-3)

108 = 2(2d+12)

108 = 4d+24

4d+24 = 108

4d = 108-24

4d = 84

d = 84/4

d = 21

The deep end is 21 feet long.

This means the overall horizontal length is d+15 = 21+15 = 36 feet and the the vertical width is d-3 = 21-3 = 18 feet

The overall dimensions of the rectangular pool are 36 ft by 18 ft

<h3>Answer:  d = 21</h3>
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cestrela7 [59]

9514 1404 393

Answer:

  a[n] = n^2 -3n -6

Step-by-step explanation:

First differences are ...

  -8 -(-8) = 0

  -6 -(-8) = 2

  -2 -(-6) = 4

Second differences are ...

  2 -0 = 2

  4 -2 = 2

Constant second differences indicate a degree 2 (quadratic) sequence.

The general formulation can be written as ...

  an = a1 +(n -1)(d1 +(n -2)/2(d2)) . . . . where a1 is the first term; d1 is the first first difference; d2 is the second difference

  = -8 +(n -1)(0 +(n -2)/2(2)) = -8 +(n -1)(n -2)

  an = n^2 -3n -6 . . . . . formula for the n-th term

7 0
3 years ago
A quadrilateral is inscribed in a circle. It's vertices divide the circle into four consecutive arcs in the ratio 1:2:5:4. Find
il63 [147K]
The angles are 30:60:150:120
4 0
3 years ago
Find the sum<br> -1,457+890+(-345)=
QveST [7]

Answer:

-912

Step-by-step explanation:

  1. Simplify: -1,457 + 890 - 345
  2. -1,457 + 890 = -567
  3. Plug -567 in: -567 - 345
  4. -567 - 345 = -912

I hope this helps!

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Domain f(x)=5^(2x-1)​
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The attached image may have what you are looking for.

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find the volume of a cylinder with a base area of 25 pi in^2 And height equal to the radius. Give your answer both in terms of p
telo118 [61]
The base of the cylinder is a circle in which the area is calculated through the equation,
                                     A = πr²
We are given that area is 25π in². From this and the equation above, the value of r is equal to 5 in. Using this calculated value as the height, the volume of the cylinder is,
                                  V = Bh
where B is area of the base and h is height. 
                                V = (25π in²)(5 in) = 125π in³ 
 or also equal to, 
                               V = 392.7 in
7 0
3 years ago
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