Answer:
2x^2-4x=3
standard form of a quadratic equation =ax^2+bx+y=0
so you would bring the 3 over to the other side making the solution 2x^2-4x-3=0
You have to multiply the 6 by both s and -9
So you will get 6s - 54 which is the answer
Answer:
well if we take -12 and divide it by four we will get -3.
Step-by-step explanation:
If we have a total of negative 12, just divide it by 4 and the difference between each division is the sum.
Your answer will be -3 on the number line.
:)
