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Molodets [167]
3 years ago
6

A dog weighs 10 lbs how many 5 mg tablets are needed to provide a dose of 7.5 mg /lb to the dog​

Mathematics
1 answer:
Virty [35]3 years ago
6 0

Answer:

15 5mg tablets

Step-by-step explanation:

The dog needs 7.5 mg a pound. He weighs 10 lbs so multiply 7.5 by 10. You get 75 so divide it by 5. Answer is 15

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Which graph represents the polynomial function g(x) = x3 + x2 – 17x + 15?
denis-greek [22]

Answer:

(x+3)⋅(x+1)⋅(x−5)

Step-by-step explanation:

4 0
3 years ago
HELP, MATH QUESTION!<br> solve xz+y+1=z<br> for z
galben [10]
Xz+y+1=z. given

y+1=z-xz. subtraction property of equality

y+1=z(1-x) distributive property of multiplication over addition/factoring

(1+y)/(1-x) = z division property of required, given x≠1
7 0
3 years ago
6x+3(4x-2)=5(2x-8) the answer is -17/4 but can someone explain how to get that answer? plz help lol​
Sergeu [11.5K]

Answer:

<h2>x =  -  \frac{17}{4}</h2>

Step-by-step explanation:

6x + 3(4x - 2) = 5(2x - 8)

Expand the terms in the bracket and simplify

That's

6x + 12x  - 6 = 10x - 40 \\ 18x - 6 = 10x - 40

Using the subtraction property subtract 10x from both sides of the equation

18x - 10x - 6 = 10x - 10x - 40 \\ 8x - 6 =  - 40

<u>Add 6 to both sides of the equation</u>

8x + 6 - 6 =  - 40 + 6 \\ 8x =  - 34

<u>Divide both sides by 8</u>

\frac{8x}{8}  =  -  \frac{34}{8}

<u>Reduce the fraction with 2</u>

We have the final answer as

x =  -  \frac{17}{4}

Hope this helps you

7 0
3 years ago
Why do we use variables in math?
Phoenix [80]

Answer:

We use it to substitute an unknown number. We have a variable for a number we don’t know and as we solve the problem we can find the answer for the variable or unknown number.

Step-by-step explanation:

I hope it helps! Have a great day!
Anygays-

8 0
1 year ago
Read 2 more answers
Here brainliest look arE the picture
satela [25.4K]

Answer:

12p = 48

3rd option

Step-by-step explanation:

total photos =48

pages on website = 12

photos on each page = p

then,

p =48/12

that is

12p =48

5 0
3 years ago
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