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Molodets [167]
3 years ago
6

A dog weighs 10 lbs how many 5 mg tablets are needed to provide a dose of 7.5 mg /lb to the dog​

Mathematics
1 answer:
Virty [35]3 years ago
6 0

Answer:

15 5mg tablets

Step-by-step explanation:

The dog needs 7.5 mg a pound. He weighs 10 lbs so multiply 7.5 by 10. You get 75 so divide it by 5. Answer is 15

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One operator is holding a laser pointer at a height of 9 feet whose beam is reflected on a horizontal reflecting surface at a po
lutik1710 [3]

Answer:

The height (in feet) at which the laser will impact the wall is 6.75 feet

Step-by-step explanation:

The given parameters are;

The height from which the laser beam operator is holding the laser = 9 feet

The horizontal distance away from the pointer the beam is reflected = 8 feet

Given that we have;

f(x) = \dfrac{9}{8} \times \left | x - 8\right | = y

When x = 8, the point of reflection, the height, f(x) is given as follows;

f(x) = \dfrac{9}{8} \times \left | 8 - 8\right | = 0

When x = 7, the point of reflection, the height, f(x) is given as follows;

f(x) = \dfrac{9}{8} \times \left | 7 - 8\right | = \dfrac{9}{8}

Therefore, given that the point of reflection is at an elevation of 0 relative to the 9 feet of the laser source (pointer), by tan rule, we have;

tan(\theta) = \dfrac{Opposite \ side}{Adjacent \ side} =\dfrac{9}{8} = \dfrac{h}{7}

Where;

h = The height at which the laser meets the wall

h = \dfrac{9 \times  7}{8} =7.875

Given that the wall the laser meets is at the point x with elevation 9/8, the height, y, at which the laser meets the wall is therefore;

y = \dfrac{9 \times  7}{8} - \dfrac{9}{8} = \dfrac{54}{8} = 6.75 \ feet

The height (in feet) at which the laser will impact the wall = 6.75 feet.

7 0
3 years ago
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