a.on , off
In most computer processors, electron movement is controlled by tiny switches that turn this flow of electricity on and off...zero represents off and one represents on
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The packet is
dropped or discarded. By default, a router will send packets
to a network that has been listed in the routing table. If it happens that the
network is not listed, the packet will be discarded or dropped. Packets that do
not have a default route or gateway of last resort are dropped.
Answer:
import java.util.Scanner;
public class DashLine {
public static void main(String[] args) {
// Declaring variables
int n;
/*
* Creating an Scanner class object which is used to get the inputs
* entered by the user
*/
Scanner sc = new Scanner(System.in);
// Getting the input entered by the user
System.out.print("Enter a number :");
n = sc.nextInt();
// calling the method by passing the user entered input as argument
dashedLine(n);
}
//This method will print the dashed line for number greater than zer
private static void dashedLine(int n) {
if (n > 0) {
for (int i = 1; i <= n; i++) {
System.out.print("-");
}
System.out.println();
}
}
}
Explanation:
Answer:
Explanation:
The following Python program uses a combination of dictionary, list, regex, and loops to accomplish what was requested. The function takes a file name as input, reads the file, and saves the individual words in a list. Then it loops through the list, adding each word into a dictionary with the number of times it appears. If the word is already in the dictionary it adds 1 to its count value. The program was tested with a file named great_expectations.txt and the output can be seen below.
import re
def wordCount(fileName):
file = open(fileName, 'r')
wordList = file.read().lower()
wordList = re.split('\s', wordList)
wordDict = {}
for word in wordList:
if word in wordDict:
wordDict[word] = wordDict.get(word) + 1
else:
wordDict[word] = 1
print(wordDict)
wordCount('great_expectations.txt')
