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vfiekz [6]
2 years ago
9

explain how a computer screen and the eye interact to produce the variety of colors that we see from the 3 colors that are actua

lly displayed on the screen ?
Computers and Technology
1 answer:
Dima020 [189]2 years ago
5 0

Answer:

Each pixel of light coming from your computer is made up of a combination of Red, Blue and Green light of different intensities. As this pixel of light is so small your eye only "sees" the combination of those 3 pixels as the intended colour. (as opposed to just red, green and blue light) (This is also known as additive colour mixing)

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Anyone from qls<br><br>or grax here<br><br>in bs​
PIT_PIT [208]

Answer:

No, I don't think I've ever heard of DLS or Grax either if I'm being honest.

May I have brainliest please? :)

7 0
2 years ago
Which characteristic of Cloud computing allows data centers to better manage hard drive failures and allocate computing resource
MrMuchimi

Answer:

When working with cloud computing, drive failures and need for usage and data is easily identifiable, so in short term, all of the things that show the user/s what needs to be done is the characteristic.

Explanation:

5 0
2 years ago
Everybody at a company is assigned a unique 9 digit ID. How many unique IDs exist?
timama [110]

Answer:

3,265,920 unique ID exist.

Explanation:

The nine digits are from 0 to 9, there are ten bits from 0 -9,

0, 1, 2, 3, 4, 5, 6, 7, 8, 9

The first is select from the highest bit (9), and the second is selected at random from 0 - 9, the third bit to the last must be unique and different from each other;

number of unique IDs = 9 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2

Multiplying the nine bits of unique IDs = 3,265,920.

3 0
2 years ago
What are the 3 biggest advancements in computers?
Georgia [21]

Answer:

abacus . Mesopotamia or China, possibly several thousand years BCE. ...

binary math . Pingala, India, 3rd century BCE. ...

punched card . Basile Bouchon, France, 1725. ...

Explanation:

:)

6 0
2 years ago
Create an application containing an array that stores eight integers. The application should call five methods that in turn (1)
Butoxors [25]

Answer:

package b4;

public class ArrayMethodDemo {

public static void main(String[] args) {

 // Create an array to store 8 random integers.

 int[] integernumbers = { 3, 4, 6, 9, 5, 6, 7, 2 };

 // Call the display method to show the elements in the array.

 display(integernumbers);

 // Call the method to display the elements in reverse order.

 displayReverse(integernumbers);

 // Call the method to find the sum of the elements.

 sum(integernumbers);

 // Call the method to display all elements less than a limiting value, say 5.

 lessThan(integernumbers, 5);

 // Call the method to display all elements greater than the average of the array

 // elements.

 higherThan(integernumbers);

}

// Method to display the elements in the array.

// The method receives only a single argument which is the array.

// Loop through the array and at every cycle, print out each element

public static void display(int[] arr) {

 System.out.print("All integers in the array : ");

 for (int i = 0; i < arr.length; i++) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to display the elements in the array in reverse order

// The method receives only a single parameter which is the array

// Loop through the array starting at the last index

// At every cycle, print out the elements in the array

public static void displayReverse(int[] arr) {

 System.out.print("All integers in the array in reverse : ");

 for (int i = arr.length - 1; i >= 0; i--) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to print out the sum of the elements in the array.

// The method receives only a single parameter which is the array.

// Declare a variable called sum to hold the sum of the elements

// Initialize sum to zero

// Loop through the array and cumulatively add each element to sum

// Print out the sum at the end of the loop

public static void sum(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 System.out.println("The sum of the integers in the array is " + sum);

}

// Method to print all values in the array that are less than a limiting

// argument.

// The method has two parameters - the array and the limiting argument.

// Loop through the array and at every cycle,

// check if the current array element is less than the limiting argument.

// If it is, print it out. Else continue

public static void lessThan(int[] arr, int limitingargument) {

 System.out.print("All values less than the limiting argument (" + limitingargument + ") are: ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] < limitingargument) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

// Method to print all values in the array that are higher than the average of

// the array.

// The method has one parameter - the array.

// First, calculate the average of the array elements.

// Loop through the array and at every cycle,

// check if the current array element is greater than the average.

// If it is, print it out. Else continue

public static void higherThan(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 double average = sum / arr.length;

 System.out.print("All values higher than the calculate average (" + average + ") is ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] > average) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

}

Explanation:

The program has been written in Java.

Please go through the comments in the code for explanation.

The source code has also been attached to this response.

Hope this helps!

Download java
3 0
3 years ago
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