-3x + y = 1 ............. the general form is y= mx +b .................y = 1 + 3x
...........................
Y = 3x + 1
<em>Greetings from Brasil</em>
From radiciation properties:
![\large{A^{\frac{P}{Q}}=\sqrt[Q]{A^P}}](https://tex.z-dn.net/?f=%5Clarge%7BA%5E%7B%5Cfrac%7BP%7D%7BQ%7D%7D%3D%5Csqrt%5BQ%5D%7BA%5EP%7D%7D)
bringing to our problem
![\large{6^{\frac{1}{3}}=\sqrt[3]{6^1}}](https://tex.z-dn.net/?f=%5Clarge%7B6%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B6%5E1%7D%7D)
<h2>∛6</h2>
Perimeter=4h+4
If the base is 2 more than the height, it gives us the equation:
b=h+2
The equation for the perimeter of a rectangle can be though of as 2b+2h, so substituting in (h+2) for b from the first equation, we get 2(h+2)+2h.
This can be simplified to be 2h+4+2h or 4h+4
4 hundreds = 4 100s = 4(100) = 400
400 is another way for writing four hundreds.
Hope this helps!
Answer:
the answer is a
Step-by-step explanation:
if you compare pm and qn pm is shorter so you see its only a little bit longer then that so its close to there.
