The solution to the system of equations is x = 3 and y = 10
<h3>How to solve the equations?</h3>
The system is given as:
2x-2y=-14
3x-y=-1
Multiply (1) by 1 and (2) by 2
So, we have:
1(2x-2y=-14)
2(3x-y=-1 )
This gives
2x - 2y=-14
6x - 2y=-2
Subtract the equations
-4x = -12
Divide by -4
x = 3
Substitute x = 3 in 3x-y=-1
3(3)-y=-1
Evaluate
9 - y = -1
Solve for y
y = 10
Hence, the solution to the system of equations is x = 3 and y = 10
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x is less than or equal to -4 or x is greater than or equal to 5
x <= -4 or x>= 5
There is no intersection of both inequalities when we graph it in number line So, we write the interval notation separately for each inequality
for x<=-4 , x starts at -4 and goes to -infinity because we have less than symbol. Also we have = sign so we use square brackets
Interval notation is (-∞ , -4]
for x>= 5 , x starts at 5 and goes to infinity because we have greater than symbol. Also we have = sign so we use square bracket at 5
Interval notation is [5 , ∞)
Now combine both notation by a 'U' symbol Union
(-∞ , -4] U [5 , ∞)
You already know that y equals -4. It says that x equals 3, so multiply the -4 by 3 and because it has a negative number and a positive number it will equal -12. Remember anytime you see a letter after a number it means multiply. The complete problem should be -10 because 2 is a whole number you subtract it from -12. Hope that helped you out some.
Answer:
19.6%
Step-by-step explanation:
You should subtract the powers when they are divided and add them when they are multiplied this rule is so important for now you just have to subtract them and you will get the answer
Hope it helps :)
