Question:
You are in a bike race. When you get to the first checkpoint, you are 2/5 of the distance to the second checkpoint. When you get to the second check point, you are 1/4 of the distance to the finish. If the entire race is 40 miles, what is the distance between the start and the first check point?
Answer: 4 miles
Step-by-step explanation:
Let distance between start to first checkpoint = x
First checkpoint to second checkpoint = 2/5 of x
Distance of start to checkpoint 1 = ( 2/5 of start to checkpoint 2)
Distance of start to checkpoint 2 = (1/4 of start to finish)
If start to checkpoint 2 = 1/4 of start to finish
Then,
Distance of start to checkpoint 1 = ( 2/5 * 1/4 of start to finish)
Distance of start to checkpoint 1 = 2/20 of start to finish = 1/10 of start to finish
Entire race = 40 miles = distance from start to finish
1/ 10 of 40
= ( 1/10) × 40
= 4 miles
The probability to pick anything other then orange is 0.86
Answer:
Option (4)
Step-by-step explanation:
Area of a rectangle = Length × width
If the dimensions of the given rectangle is doubled,
Area of the new rectangle = 2(Length) × 2(width)
= 4(Length × width)
= 4(x)(x - 2)
= 4[x² - 2x]
= 4x² - 8x
Therefore, Option (4) will be the correct option.
Answer:
For this one the parallel slope is going to be 2/5
Step-by-step explanation:
Answer:
The 90% confidence interval estimate of the mean of the population is between 6627 and 6941.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 15 - 1 = 14
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 1.761
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 6784 - 157 = 6627
The upper end of the interval is the sample mean added to M. So it is 6784 + 157 = 6941
The 90% confidence interval estimate of the mean of the population is between 6627 and 6941.
